prove: if $abmid cd$ and $amid c$ and $abnmid c$ then $bmid d$ [closed]Find $a$, $b$, and $c$ so $a mid bc ~$ but $a nmid b space $ and $a nmid c$Proving by absurd that $d nmid 4,5,10, 20$Divisibility: if $a mid b$ and $b mid c$, then $a mid (b+c)$Prove that $2k+5 mid kin mathbbZ = 2k+3 mid kin mathbbZ$.Show $nexists k:3^7mid k!$ but $3^8nmid k!$Prove if (a,p)=1, then a,2a,3a,…,pa is a complete residue system modulo p.if $5nmid a$ or $5nmid b$, then $5nmid a^2-2b^2$.Prove that if $amid(b-1)$ and $a^2mid(b^2-2b+4)$, then $amid12$.If $12mida$ then $4nmidb$ or $4mid(8+2a+5b)$.
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prove: if $abmid cd$ and $amid c$ and $abnmid c$ then $bmid d$ [closed]
Find $a$, $b$, and $c$ so $a mid bc ~$ but $a nmid b space $ and $a nmid c$Proving by absurd that $d nmid 4,5,10, 20$Divisibility: if $a mid b$ and $b mid c$, then $a mid (b+c)$Prove that $2k+5 mid kin mathbbZ = 2k+3 mid kin mathbbZ$.Show $nexists k:3^7mid k!$ but $3^8nmid k!$Prove if (a,p)=1, then a,2a,3a,…,pa is a complete residue system modulo p.if $5nmid a$ or $5nmid b$, then $5nmid a^2-2b^2$.Prove that if $amid(b-1)$ and $a^2mid(b^2-2b+4)$, then $amid12$.If $12mida$ then $4nmidb$ or $4mid(8+2a+5b)$.
$begingroup$
I'm having a hard time proving the following claim:
if $abmid cd$ and $amid c$ and $abnmid c$ then $bmid d$
Any help would be appreciated
elementary-number-theory divisibility
edited Mar 12 at 20:19
Jennifer
8,60521837
asked Mar 12 at 20:17
user5842084user5842084
1
New contributor
user5842084 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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closed as off-topic by Eevee Trainer, Clayton, Vinyl_cape_jawa, Shaun, RRL Mar 12 at 22:52
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Eevee Trainer, Clayton, Vinyl_cape_jawa, Shaun, RRL
add a comment |
$begingroup$
I'm having a hard time proving the following claim:
if $abmid cd$ and $amid c$ and $abnmid c$ then $bmid d$
Any help would be appreciated
elementary-number-theory divisibility
edited Mar 12 at 20:19
Jennifer
8,60521837
asked Mar 12 at 20:17
user5842084user5842084
1
New contributor
user5842084 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
closed as off-topic by Eevee Trainer, Clayton, Vinyl_cape_jawa, Shaun, RRL Mar 12 at 22:52
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Eevee Trainer, Clayton, Vinyl_cape_jawa, Shaun, RRL
$begingroup$
What have you tried so far?
$endgroup$
– Vinyl_cape_jawa
Mar 12 at 20:26
$begingroup$
$abnmid c,$ doesn't suffice, we need $(b,c/a)=1$ or equivalently $(ab,c)=a $
$endgroup$
– Bill Dubuque
Mar 12 at 21:07
add a comment |
$begingroup$
I'm having a hard time proving the following claim:
if $abmid cd$ and $amid c$ and $abnmid c$ then $bmid d$
Any help would be appreciated
elementary-number-theory divisibility
edited Mar 12 at 20:19
Jennifer
8,60521837
asked Mar 12 at 20:17
user5842084user5842084
1
New contributor
user5842084 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I'm having a hard time proving the following claim:
if $abmid cd$ and $amid c$ and $abnmid c$ then $bmid d$
Any help would be appreciated
elementary-number-theory divisibility
elementary-number-theory divisibility
edited Mar 12 at 20:19
Jennifer
8,60521837
asked Mar 12 at 20:17
user5842084user5842084
1
New contributor
user5842084 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 12 at 20:19
Jennifer
8,60521837
asked Mar 12 at 20:17
user5842084user5842084
1
New contributor
user5842084 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 12 at 20:19
Jennifer
8,60521837
edited Mar 12 at 20:19
Jennifer
8,60521837
edited Mar 12 at 20:19
Jennifer
8,60521837
8,60521837
asked Mar 12 at 20:17
user5842084user5842084
1
New contributor
user5842084 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 12 at 20:17
user5842084user5842084
1
asked Mar 12 at 20:17
user5842084user5842084
1
1
New contributor
user5842084 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user5842084 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user5842084 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
closed as off-topic by Eevee Trainer, Clayton, Vinyl_cape_jawa, Shaun, RRL Mar 12 at 22:52
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Eevee Trainer, Clayton, Vinyl_cape_jawa, Shaun, RRL
closed as off-topic by Eevee Trainer, Clayton, Vinyl_cape_jawa, Shaun, RRL Mar 12 at 22:52
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Eevee Trainer, Clayton, Vinyl_cape_jawa, Shaun, RRL
$begingroup$
What have you tried so far?
$endgroup$
– Vinyl_cape_jawa
Mar 12 at 20:26
$begingroup$
$abnmid c,$ doesn't suffice, we need $(b,c/a)=1$ or equivalently $(ab,c)=a $
$endgroup$
– Bill Dubuque
Mar 12 at 21:07
add a comment |
$begingroup$
What have you tried so far?
$endgroup$
– Vinyl_cape_jawa
Mar 12 at 20:26
$begingroup$
$abnmid c,$ doesn't suffice, we need $(b,c/a)=1$ or equivalently $(ab,c)=a $
$endgroup$
– Bill Dubuque
Mar 12 at 21:07
$begingroup$
What have you tried so far?
$endgroup$
– Vinyl_cape_jawa
Mar 12 at 20:26
$begingroup$
What have you tried so far?
$endgroup$
– Vinyl_cape_jawa
Mar 12 at 20:26
$begingroup$
$abnmid c,$ doesn't suffice, we need $(b,c/a)=1$ or equivalently $(ab,c)=a $
$endgroup$
– Bill Dubuque
Mar 12 at 21:07
$begingroup$
$abnmid c,$ doesn't suffice, we need $(b,c/a)=1$ or equivalently $(ab,c)=a $
$endgroup$
– Bill Dubuque
Mar 12 at 21:07
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Counterexample: $a=1,,b=4,,c=d=2$.
answered Mar 12 at 20:30
J.G.J.G.
30.5k23149
$endgroup$
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Counterexample: $a=1,,b=4,,c=d=2$.
answered Mar 12 at 20:30
J.G.J.G.
30.5k23149
$endgroup$
add a comment |
$begingroup$
Counterexample: $a=1,,b=4,,c=d=2$.
answered Mar 12 at 20:30
J.G.J.G.
30.5k23149
$endgroup$
add a comment |
$begingroup$
Counterexample: $a=1,,b=4,,c=d=2$.
answered Mar 12 at 20:30
J.G.J.G.
30.5k23149
$endgroup$
Counterexample: $a=1,,b=4,,c=d=2$.
answered Mar 12 at 20:30
J.G.J.G.
30.5k23149
answered Mar 12 at 20:30
J.G.J.G.
30.5k23149
answered Mar 12 at 20:30
J.G.J.G.
30.5k23149
answered Mar 12 at 20:30
J.G.J.G.
30.5k23149
30.5k23149
add a comment |
add a comment |
$begingroup$
What have you tried so far?
$endgroup$
– Vinyl_cape_jawa
Mar 12 at 20:26
$begingroup$
$abnmid c,$ doesn't suffice, we need $(b,c/a)=1$ or equivalently $(ab,c)=a $
$endgroup$
– Bill Dubuque
Mar 12 at 21:07