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Why Lagrangians of two (real) torus are lines?



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Question about $4$-manifolds and intersection formsDefinition of symplectic mapTrouble understanding proof of this proposition on contact type hypersurfacesPerburb the Monodromy of Lefschetz fibration over a diskMirror Symmetry of Elliptic CurvePoincaré–Bendixson theorem on the torusWhat is mirror of symplectic $mathbbCP^2$?Why is the matrix in Dirac's bracket formula invertible?Gompf's symplectic sum construction and symplectic involution of annulusRescaling a symplectic form and integral cohomology










1












$begingroup$


I am reading an article on Mirror Symmetry, where an example is given : the two (real) dimensional torus.



My question is a basic one : taking the symplectic form (if ones focuses on the symplectic aspect) to be the area form, the author says that Lagrangians (submanifolds closed by this form) are just lines.



Is this simply because lines are the zero area submanifolds?
Why there aren't more than these?



Thank you.










share|cite|improve this question











$endgroup$
















    1












    $begingroup$


    I am reading an article on Mirror Symmetry, where an example is given : the two (real) dimensional torus.



    My question is a basic one : taking the symplectic form (if ones focuses on the symplectic aspect) to be the area form, the author says that Lagrangians (submanifolds closed by this form) are just lines.



    Is this simply because lines are the zero area submanifolds?
    Why there aren't more than these?



    Thank you.










    share|cite|improve this question











    $endgroup$














      1












      1








      1





      $begingroup$


      I am reading an article on Mirror Symmetry, where an example is given : the two (real) dimensional torus.



      My question is a basic one : taking the symplectic form (if ones focuses on the symplectic aspect) to be the area form, the author says that Lagrangians (submanifolds closed by this form) are just lines.



      Is this simply because lines are the zero area submanifolds?
      Why there aren't more than these?



      Thank you.










      share|cite|improve this question











      $endgroup$




      I am reading an article on Mirror Symmetry, where an example is given : the two (real) dimensional torus.



      My question is a basic one : taking the symplectic form (if ones focuses on the symplectic aspect) to be the area form, the author says that Lagrangians (submanifolds closed by this form) are just lines.



      Is this simply because lines are the zero area submanifolds?
      Why there aren't more than these?



      Thank you.







      manifolds symplectic-geometry mirror-symmetry






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 25 at 10:08









      Andrews

      1,2962423




      1,2962423










      asked Sep 20 '18 at 20:36









      vanmerivanmeri

      709




      709




















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