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Binomial Distribution test or Comparing Proportions test?



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Hypothesis Testing of the normal distributiontwo sample t-test not matching RExact interpretration of p-value and significance of testHow to prove a given statistical test has the greatest powerComparing expected counts to observed countsNull Hypothesis and Binomial DistributionSign Test for Hypothesized Medianprove if one sample t test accept null hypothesis then one sample sign test must accept the null hypothesiscalculate sample size for specified type II error probability, comparing 2 proportionscalculating test statistic for comparison of two proportions










0












$begingroup$


I've been posed the following question:
enter image description here



Initially, I tried approaching this question by applying a 'comparing proportions' test on the information given. However, there is insufficient information; I cannot calculate the test statistic because the successes and sample size for global influenza is not given. Should I approach this question with null hypothesis: $H0 = mean(oceania) = mean (global)
$
?










share|cite|improve this question









$endgroup$











  • $begingroup$
    The population of Oceania is around $40$ million (depending on definition) compared with a world population of around $7,600$ million so I would suggest you test $H_0: text Type A proportion in Oceania = 0.842$ and $H_1: text Type A proportion in Oceania not= 0.842$
    $endgroup$
    – Henry
    Mar 25 at 8:39











  • $begingroup$
    note that the global proportion $0.842$ is the population parameter, not a sample statistic, therefore you must test one-sample (not two-sample) hypothesis test. It would be two-sample, if two samples were selected from two populations (regions). So, the correct hypotheses: $H_0: p=0.842, H_a:pne 0.842$.
    $endgroup$
    – farruhota
    Mar 25 at 8:43










  • $begingroup$
    Thanks both for your help! much appreciated :)
    $endgroup$
    – lohboys
    Mar 25 at 8:54










  • $begingroup$
    math.meta.stackexchange.com/questions/29995/…
    $endgroup$
    – user657581
    Mar 25 at 9:08















0












$begingroup$


I've been posed the following question:
enter image description here



Initially, I tried approaching this question by applying a 'comparing proportions' test on the information given. However, there is insufficient information; I cannot calculate the test statistic because the successes and sample size for global influenza is not given. Should I approach this question with null hypothesis: $H0 = mean(oceania) = mean (global)
$
?










share|cite|improve this question









$endgroup$











  • $begingroup$
    The population of Oceania is around $40$ million (depending on definition) compared with a world population of around $7,600$ million so I would suggest you test $H_0: text Type A proportion in Oceania = 0.842$ and $H_1: text Type A proportion in Oceania not= 0.842$
    $endgroup$
    – Henry
    Mar 25 at 8:39











  • $begingroup$
    note that the global proportion $0.842$ is the population parameter, not a sample statistic, therefore you must test one-sample (not two-sample) hypothesis test. It would be two-sample, if two samples were selected from two populations (regions). So, the correct hypotheses: $H_0: p=0.842, H_a:pne 0.842$.
    $endgroup$
    – farruhota
    Mar 25 at 8:43










  • $begingroup$
    Thanks both for your help! much appreciated :)
    $endgroup$
    – lohboys
    Mar 25 at 8:54










  • $begingroup$
    math.meta.stackexchange.com/questions/29995/…
    $endgroup$
    – user657581
    Mar 25 at 9:08













0












0








0





$begingroup$


I've been posed the following question:
enter image description here



Initially, I tried approaching this question by applying a 'comparing proportions' test on the information given. However, there is insufficient information; I cannot calculate the test statistic because the successes and sample size for global influenza is not given. Should I approach this question with null hypothesis: $H0 = mean(oceania) = mean (global)
$
?










share|cite|improve this question









$endgroup$




I've been posed the following question:
enter image description here



Initially, I tried approaching this question by applying a 'comparing proportions' test on the information given. However, there is insufficient information; I cannot calculate the test statistic because the successes and sample size for global influenza is not given. Should I approach this question with null hypothesis: $H0 = mean(oceania) = mean (global)
$
?







statistics






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 25 at 8:31









lohboyslohboys

10319




10319











  • $begingroup$
    The population of Oceania is around $40$ million (depending on definition) compared with a world population of around $7,600$ million so I would suggest you test $H_0: text Type A proportion in Oceania = 0.842$ and $H_1: text Type A proportion in Oceania not= 0.842$
    $endgroup$
    – Henry
    Mar 25 at 8:39











  • $begingroup$
    note that the global proportion $0.842$ is the population parameter, not a sample statistic, therefore you must test one-sample (not two-sample) hypothesis test. It would be two-sample, if two samples were selected from two populations (regions). So, the correct hypotheses: $H_0: p=0.842, H_a:pne 0.842$.
    $endgroup$
    – farruhota
    Mar 25 at 8:43










  • $begingroup$
    Thanks both for your help! much appreciated :)
    $endgroup$
    – lohboys
    Mar 25 at 8:54










  • $begingroup$
    math.meta.stackexchange.com/questions/29995/…
    $endgroup$
    – user657581
    Mar 25 at 9:08
















  • $begingroup$
    The population of Oceania is around $40$ million (depending on definition) compared with a world population of around $7,600$ million so I would suggest you test $H_0: text Type A proportion in Oceania = 0.842$ and $H_1: text Type A proportion in Oceania not= 0.842$
    $endgroup$
    – Henry
    Mar 25 at 8:39











  • $begingroup$
    note that the global proportion $0.842$ is the population parameter, not a sample statistic, therefore you must test one-sample (not two-sample) hypothesis test. It would be two-sample, if two samples were selected from two populations (regions). So, the correct hypotheses: $H_0: p=0.842, H_a:pne 0.842$.
    $endgroup$
    – farruhota
    Mar 25 at 8:43










  • $begingroup$
    Thanks both for your help! much appreciated :)
    $endgroup$
    – lohboys
    Mar 25 at 8:54










  • $begingroup$
    math.meta.stackexchange.com/questions/29995/…
    $endgroup$
    – user657581
    Mar 25 at 9:08















$begingroup$
The population of Oceania is around $40$ million (depending on definition) compared with a world population of around $7,600$ million so I would suggest you test $H_0: text Type A proportion in Oceania = 0.842$ and $H_1: text Type A proportion in Oceania not= 0.842$
$endgroup$
– Henry
Mar 25 at 8:39





$begingroup$
The population of Oceania is around $40$ million (depending on definition) compared with a world population of around $7,600$ million so I would suggest you test $H_0: text Type A proportion in Oceania = 0.842$ and $H_1: text Type A proportion in Oceania not= 0.842$
$endgroup$
– Henry
Mar 25 at 8:39













$begingroup$
note that the global proportion $0.842$ is the population parameter, not a sample statistic, therefore you must test one-sample (not two-sample) hypothesis test. It would be two-sample, if two samples were selected from two populations (regions). So, the correct hypotheses: $H_0: p=0.842, H_a:pne 0.842$.
$endgroup$
– farruhota
Mar 25 at 8:43




$begingroup$
note that the global proportion $0.842$ is the population parameter, not a sample statistic, therefore you must test one-sample (not two-sample) hypothesis test. It would be two-sample, if two samples were selected from two populations (regions). So, the correct hypotheses: $H_0: p=0.842, H_a:pne 0.842$.
$endgroup$
– farruhota
Mar 25 at 8:43












$begingroup$
Thanks both for your help! much appreciated :)
$endgroup$
– lohboys
Mar 25 at 8:54




$begingroup$
Thanks both for your help! much appreciated :)
$endgroup$
– lohboys
Mar 25 at 8:54












$begingroup$
math.meta.stackexchange.com/questions/29995/…
$endgroup$
– user657581
Mar 25 at 9:08




$begingroup$
math.meta.stackexchange.com/questions/29995/…
$endgroup$
– user657581
Mar 25 at 9:08










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