Solving $1=Gammaleft(fracd2right)-Gammaleft(fracd2, 2t right)$Solving for a variable under $Gamma(z)$Solve equation with lower gamma function: $A gamma(2;x/B)=x$ for $x$Is it possible to simplify $fracGammaleft(frac110right)Gammaleft(frac215right) Gammaleft(frac715right)$?Series expansion of incomplete gamma function ratioProof of $Gamma(x)Gammaleft(dfrac1xright)gt 1$Integral of exponential, polynomial and gamma functionIncomplete Gamma function of negative argumentsSeries of Gamma functions involving $Gamma left(fracn2 (1-i x)right) Gamma left(fracn2 (1+i x)right)$?Is there a way to simplify $lnleft[ Gammaleft( i x right) right] - lnleft[ Gammaleft( i y right) right]$?Solving $Releft[Gamma(n, bi)right]$

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Solving $1=Gammaleft(fracd2right)-Gammaleft(fracd2, 2t right)$


Solving for a variable under $Gamma(z)$Solve equation with lower gamma function: $A gamma(2;x/B)=x$ for $x$Is it possible to simplify $fracGammaleft(frac110right)Gammaleft(frac215right) Gammaleft(frac715right)$?Series expansion of incomplete gamma function ratioProof of $Gamma(x)Gammaleft(dfrac1xright)gt 1$Integral of exponential, polynomial and gamma functionIncomplete Gamma function of negative argumentsSeries of Gamma functions involving $Gamma left(fracn2 (1-i x)right) Gamma left(fracn2 (1+i x)right)$?Is there a way to simplify $lnleft[ Gammaleft( i x right) right] - lnleft[ Gammaleft( i y right) right]$?Solving $Releft[Gamma(n, bi)right]$













2












$begingroup$


Is it possible to solve the following equation that contain the incomplete Gamma function?



$$1=Gammaleft(dfracd2right)-Gammaleft(dfracd2, 2t right)$$



I would like to find the value of $d$, but I do not know if there is a way.



$t$ can take any positive value.










share|cite|improve this question











$endgroup$











  • $begingroup$
    Am I correct to interpret this as you would like to know for which $d$ the lower incomplete gamma function $gamma(d/2,2t) = int_0^2t s^-d/2-1e^-sds = 1$? What to you mean for when $ttoinfty$? Then you are left with $Gamma(d/2) = 1$?
    $endgroup$
    – Sisyphus
    Mar 22 at 18:05










  • $begingroup$
    Yes, finally I could compute when $t$ goes to infinity, where $d$ is either 2 or 4. The problem is when I say for any $t$. Perhaps I should edit the question.
    $endgroup$
    – Mounia Hamidouche
    Mar 23 at 0:12
















2












$begingroup$


Is it possible to solve the following equation that contain the incomplete Gamma function?



$$1=Gammaleft(dfracd2right)-Gammaleft(dfracd2, 2t right)$$



I would like to find the value of $d$, but I do not know if there is a way.



$t$ can take any positive value.










share|cite|improve this question











$endgroup$











  • $begingroup$
    Am I correct to interpret this as you would like to know for which $d$ the lower incomplete gamma function $gamma(d/2,2t) = int_0^2t s^-d/2-1e^-sds = 1$? What to you mean for when $ttoinfty$? Then you are left with $Gamma(d/2) = 1$?
    $endgroup$
    – Sisyphus
    Mar 22 at 18:05










  • $begingroup$
    Yes, finally I could compute when $t$ goes to infinity, where $d$ is either 2 or 4. The problem is when I say for any $t$. Perhaps I should edit the question.
    $endgroup$
    – Mounia Hamidouche
    Mar 23 at 0:12














2












2








2





$begingroup$


Is it possible to solve the following equation that contain the incomplete Gamma function?



$$1=Gammaleft(dfracd2right)-Gammaleft(dfracd2, 2t right)$$



I would like to find the value of $d$, but I do not know if there is a way.



$t$ can take any positive value.










share|cite|improve this question











$endgroup$




Is it possible to solve the following equation that contain the incomplete Gamma function?



$$1=Gammaleft(dfracd2right)-Gammaleft(dfracd2, 2t right)$$



I would like to find the value of $d$, but I do not know if there is a way.



$t$ can take any positive value.







special-functions gamma-function






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 23 at 7:35









J. M. is not a mathematician

61.2k5152290




61.2k5152290










asked Mar 22 at 16:00









Mounia HamidoucheMounia Hamidouche

34719




34719











  • $begingroup$
    Am I correct to interpret this as you would like to know for which $d$ the lower incomplete gamma function $gamma(d/2,2t) = int_0^2t s^-d/2-1e^-sds = 1$? What to you mean for when $ttoinfty$? Then you are left with $Gamma(d/2) = 1$?
    $endgroup$
    – Sisyphus
    Mar 22 at 18:05










  • $begingroup$
    Yes, finally I could compute when $t$ goes to infinity, where $d$ is either 2 or 4. The problem is when I say for any $t$. Perhaps I should edit the question.
    $endgroup$
    – Mounia Hamidouche
    Mar 23 at 0:12

















  • $begingroup$
    Am I correct to interpret this as you would like to know for which $d$ the lower incomplete gamma function $gamma(d/2,2t) = int_0^2t s^-d/2-1e^-sds = 1$? What to you mean for when $ttoinfty$? Then you are left with $Gamma(d/2) = 1$?
    $endgroup$
    – Sisyphus
    Mar 22 at 18:05










  • $begingroup$
    Yes, finally I could compute when $t$ goes to infinity, where $d$ is either 2 or 4. The problem is when I say for any $t$. Perhaps I should edit the question.
    $endgroup$
    – Mounia Hamidouche
    Mar 23 at 0:12
















$begingroup$
Am I correct to interpret this as you would like to know for which $d$ the lower incomplete gamma function $gamma(d/2,2t) = int_0^2t s^-d/2-1e^-sds = 1$? What to you mean for when $ttoinfty$? Then you are left with $Gamma(d/2) = 1$?
$endgroup$
– Sisyphus
Mar 22 at 18:05




$begingroup$
Am I correct to interpret this as you would like to know for which $d$ the lower incomplete gamma function $gamma(d/2,2t) = int_0^2t s^-d/2-1e^-sds = 1$? What to you mean for when $ttoinfty$? Then you are left with $Gamma(d/2) = 1$?
$endgroup$
– Sisyphus
Mar 22 at 18:05












$begingroup$
Yes, finally I could compute when $t$ goes to infinity, where $d$ is either 2 or 4. The problem is when I say for any $t$. Perhaps I should edit the question.
$endgroup$
– Mounia Hamidouche
Mar 23 at 0:12





$begingroup$
Yes, finally I could compute when $t$ goes to infinity, where $d$ is either 2 or 4. The problem is when I say for any $t$. Perhaps I should edit the question.
$endgroup$
– Mounia Hamidouche
Mar 23 at 0:12











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