Can someone help? need to find the a and b for this function. Anything helps!! [closed]Need this Function ExplainedNeed a function for the following…Wrong implementation of functionIf A is a countable set, and B is an uncountable set, then why A intersect B is a countable set?Typo in a calculus bookCan one solve for $x$ in the equation $8^x=16x$Find z^3 give a defined functionFind the largest possible domain and the largest possible range of $F(x)$Find the value of differentiated functionLooking for a function that gives value of 0 to 1 with input of 0 to 1
Is every set a filtered colimit of finite sets?
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Can someone help? need to find the a and b for this function. Anything helps!! [closed]
Need this Function ExplainedNeed a function for the following…Wrong implementation of functionIf A is a countable set, and B is an uncountable set, then why A intersect B is a countable set?Typo in a calculus bookCan one solve for $x$ in the equation $8^x=16x$Find z^3 give a defined functionFind the largest possible domain and the largest possible range of $F(x)$Find the value of differentiated functionLooking for a function that gives value of 0 to 1 with input of 0 to 1
$begingroup$
enter image description here
Function is $f(x)= ax^4-25x^3+2x^2+25x+b $
it passes through (7,E) E= 1296 and there is a zero of -1
functional-analysis analysis functions exponential-function advice
$endgroup$
closed as off-topic by Shailesh, dantopa, Strants, John Douma, Parcly Taxel Mar 26 at 3:26
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shailesh, dantopa, Strants, John Douma, Parcly Taxel
add a comment |
$begingroup$
enter image description here
Function is $f(x)= ax^4-25x^3+2x^2+25x+b $
it passes through (7,E) E= 1296 and there is a zero of -1
functional-analysis analysis functions exponential-function advice
$endgroup$
closed as off-topic by Shailesh, dantopa, Strants, John Douma, Parcly Taxel Mar 26 at 3:26
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shailesh, dantopa, Strants, John Douma, Parcly Taxel
3
$begingroup$
Please do not use pictures for critical portions of your post. Pictures may not be legible, cannot be searched and are not view-able to some, such as those who use screen readers.
$endgroup$
– Brian
Mar 22 at 14:32
$begingroup$
Welcome to stackexchange. When you edit the question to ask it directly rather than with a hard to read image, be sure to tell us what you tried and where you are stuck. Please use mathjax: math.meta.stackexchange.com/questions/5020/…
$endgroup$
– Ethan Bolker
Mar 22 at 14:35
$begingroup$
@EnriqueRodriguez Please add the function and your work into your question. If you show your effort appropriately, it is more likely that somebody will also put his/her effort into providing you some help.
$endgroup$
– Ertxiem
Mar 22 at 14:42
$begingroup$
@Ertxiem is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:22
$begingroup$
@Brian i added the function is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:23
add a comment |
$begingroup$
enter image description here
Function is $f(x)= ax^4-25x^3+2x^2+25x+b $
it passes through (7,E) E= 1296 and there is a zero of -1
functional-analysis analysis functions exponential-function advice
$endgroup$
enter image description here
Function is $f(x)= ax^4-25x^3+2x^2+25x+b $
it passes through (7,E) E= 1296 and there is a zero of -1
functional-analysis analysis functions exponential-function advice
functional-analysis analysis functions exponential-function advice
edited Mar 22 at 15:50
CiaPan
10.3k11248
10.3k11248
asked Mar 22 at 14:29
Enrique RodriguezEnrique Rodriguez
32
32
closed as off-topic by Shailesh, dantopa, Strants, John Douma, Parcly Taxel Mar 26 at 3:26
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shailesh, dantopa, Strants, John Douma, Parcly Taxel
closed as off-topic by Shailesh, dantopa, Strants, John Douma, Parcly Taxel Mar 26 at 3:26
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shailesh, dantopa, Strants, John Douma, Parcly Taxel
3
$begingroup$
Please do not use pictures for critical portions of your post. Pictures may not be legible, cannot be searched and are not view-able to some, such as those who use screen readers.
$endgroup$
– Brian
Mar 22 at 14:32
$begingroup$
Welcome to stackexchange. When you edit the question to ask it directly rather than with a hard to read image, be sure to tell us what you tried and where you are stuck. Please use mathjax: math.meta.stackexchange.com/questions/5020/…
$endgroup$
– Ethan Bolker
Mar 22 at 14:35
$begingroup$
@EnriqueRodriguez Please add the function and your work into your question. If you show your effort appropriately, it is more likely that somebody will also put his/her effort into providing you some help.
$endgroup$
– Ertxiem
Mar 22 at 14:42
$begingroup$
@Ertxiem is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:22
$begingroup$
@Brian i added the function is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:23
add a comment |
3
$begingroup$
Please do not use pictures for critical portions of your post. Pictures may not be legible, cannot be searched and are not view-able to some, such as those who use screen readers.
$endgroup$
– Brian
Mar 22 at 14:32
$begingroup$
Welcome to stackexchange. When you edit the question to ask it directly rather than with a hard to read image, be sure to tell us what you tried and where you are stuck. Please use mathjax: math.meta.stackexchange.com/questions/5020/…
$endgroup$
– Ethan Bolker
Mar 22 at 14:35
$begingroup$
@EnriqueRodriguez Please add the function and your work into your question. If you show your effort appropriately, it is more likely that somebody will also put his/her effort into providing you some help.
$endgroup$
– Ertxiem
Mar 22 at 14:42
$begingroup$
@Ertxiem is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:22
$begingroup$
@Brian i added the function is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:23
3
3
$begingroup$
Please do not use pictures for critical portions of your post. Pictures may not be legible, cannot be searched and are not view-able to some, such as those who use screen readers.
$endgroup$
– Brian
Mar 22 at 14:32
$begingroup$
Please do not use pictures for critical portions of your post. Pictures may not be legible, cannot be searched and are not view-able to some, such as those who use screen readers.
$endgroup$
– Brian
Mar 22 at 14:32
$begingroup$
Welcome to stackexchange. When you edit the question to ask it directly rather than with a hard to read image, be sure to tell us what you tried and where you are stuck. Please use mathjax: math.meta.stackexchange.com/questions/5020/…
$endgroup$
– Ethan Bolker
Mar 22 at 14:35
$begingroup$
Welcome to stackexchange. When you edit the question to ask it directly rather than with a hard to read image, be sure to tell us what you tried and where you are stuck. Please use mathjax: math.meta.stackexchange.com/questions/5020/…
$endgroup$
– Ethan Bolker
Mar 22 at 14:35
$begingroup$
@EnriqueRodriguez Please add the function and your work into your question. If you show your effort appropriately, it is more likely that somebody will also put his/her effort into providing you some help.
$endgroup$
– Ertxiem
Mar 22 at 14:42
$begingroup$
@EnriqueRodriguez Please add the function and your work into your question. If you show your effort appropriately, it is more likely that somebody will also put his/her effort into providing you some help.
$endgroup$
– Ertxiem
Mar 22 at 14:42
$begingroup$
@Ertxiem is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:22
$begingroup$
@Ertxiem is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:22
$begingroup$
@Brian i added the function is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:23
$begingroup$
@Brian i added the function is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:23
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You can find $a$ and $b$ as a system of equations:
We know that for $x=7$, $f(x)=1296$, this will be one equation on $a$ and $b$.
And for $x=-1$, $f(x) = 0$, this will give another equation on $a$ and $b$.
Can you write down the equations and solve the system or do you need more help?
Edit: The equations will be:
$$begincases
a times 7^4 - 25 times 7^3 + 2 times 7^2+25 times 7 + b = 1296 \
a times (-1)^4 - 25 times (-1)^3 + 2 times (-1)^2+25 times (-1) + b = 0
endcases$$
Edit 2: If you subtract the first equation from the second you get an equation without $b$:
$$a times (7^4-(-1)^4) - 25 times (7^3-(-1)^3) + 2 times (7^2-(-1)^2) + 25 times (7-(-1)) = 1296 .$$
I was a bit lazy and I did not compute the powers of $7$. :)
With this last equation, you'll be able to compute the value of $a$. To obtain the value of $b$ you can use one of the other equations (I suggest using the one with the smaller numbers).
$endgroup$
$begingroup$
this helps could you help me a little more?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:32
$begingroup$
just with the equations
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:40
$begingroup$
still a little confused first time doing this! how do i get the a and b out of this 2 equations? cause a and b are still both in there? i can slove when its one variable but not 2.
$endgroup$
– Enrique Rodriguez
Mar 22 at 16:01
$begingroup$
@EnriqueRodriguez: I added another step in the solution. I believe that you can now compute the final result on your own.
$endgroup$
– Ertxiem
Mar 22 at 19:30
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can find $a$ and $b$ as a system of equations:
We know that for $x=7$, $f(x)=1296$, this will be one equation on $a$ and $b$.
And for $x=-1$, $f(x) = 0$, this will give another equation on $a$ and $b$.
Can you write down the equations and solve the system or do you need more help?
Edit: The equations will be:
$$begincases
a times 7^4 - 25 times 7^3 + 2 times 7^2+25 times 7 + b = 1296 \
a times (-1)^4 - 25 times (-1)^3 + 2 times (-1)^2+25 times (-1) + b = 0
endcases$$
Edit 2: If you subtract the first equation from the second you get an equation without $b$:
$$a times (7^4-(-1)^4) - 25 times (7^3-(-1)^3) + 2 times (7^2-(-1)^2) + 25 times (7-(-1)) = 1296 .$$
I was a bit lazy and I did not compute the powers of $7$. :)
With this last equation, you'll be able to compute the value of $a$. To obtain the value of $b$ you can use one of the other equations (I suggest using the one with the smaller numbers).
$endgroup$
$begingroup$
this helps could you help me a little more?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:32
$begingroup$
just with the equations
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:40
$begingroup$
still a little confused first time doing this! how do i get the a and b out of this 2 equations? cause a and b are still both in there? i can slove when its one variable but not 2.
$endgroup$
– Enrique Rodriguez
Mar 22 at 16:01
$begingroup$
@EnriqueRodriguez: I added another step in the solution. I believe that you can now compute the final result on your own.
$endgroup$
– Ertxiem
Mar 22 at 19:30
add a comment |
$begingroup$
You can find $a$ and $b$ as a system of equations:
We know that for $x=7$, $f(x)=1296$, this will be one equation on $a$ and $b$.
And for $x=-1$, $f(x) = 0$, this will give another equation on $a$ and $b$.
Can you write down the equations and solve the system or do you need more help?
Edit: The equations will be:
$$begincases
a times 7^4 - 25 times 7^3 + 2 times 7^2+25 times 7 + b = 1296 \
a times (-1)^4 - 25 times (-1)^3 + 2 times (-1)^2+25 times (-1) + b = 0
endcases$$
Edit 2: If you subtract the first equation from the second you get an equation without $b$:
$$a times (7^4-(-1)^4) - 25 times (7^3-(-1)^3) + 2 times (7^2-(-1)^2) + 25 times (7-(-1)) = 1296 .$$
I was a bit lazy and I did not compute the powers of $7$. :)
With this last equation, you'll be able to compute the value of $a$. To obtain the value of $b$ you can use one of the other equations (I suggest using the one with the smaller numbers).
$endgroup$
$begingroup$
this helps could you help me a little more?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:32
$begingroup$
just with the equations
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:40
$begingroup$
still a little confused first time doing this! how do i get the a and b out of this 2 equations? cause a and b are still both in there? i can slove when its one variable but not 2.
$endgroup$
– Enrique Rodriguez
Mar 22 at 16:01
$begingroup$
@EnriqueRodriguez: I added another step in the solution. I believe that you can now compute the final result on your own.
$endgroup$
– Ertxiem
Mar 22 at 19:30
add a comment |
$begingroup$
You can find $a$ and $b$ as a system of equations:
We know that for $x=7$, $f(x)=1296$, this will be one equation on $a$ and $b$.
And for $x=-1$, $f(x) = 0$, this will give another equation on $a$ and $b$.
Can you write down the equations and solve the system or do you need more help?
Edit: The equations will be:
$$begincases
a times 7^4 - 25 times 7^3 + 2 times 7^2+25 times 7 + b = 1296 \
a times (-1)^4 - 25 times (-1)^3 + 2 times (-1)^2+25 times (-1) + b = 0
endcases$$
Edit 2: If you subtract the first equation from the second you get an equation without $b$:
$$a times (7^4-(-1)^4) - 25 times (7^3-(-1)^3) + 2 times (7^2-(-1)^2) + 25 times (7-(-1)) = 1296 .$$
I was a bit lazy and I did not compute the powers of $7$. :)
With this last equation, you'll be able to compute the value of $a$. To obtain the value of $b$ you can use one of the other equations (I suggest using the one with the smaller numbers).
$endgroup$
You can find $a$ and $b$ as a system of equations:
We know that for $x=7$, $f(x)=1296$, this will be one equation on $a$ and $b$.
And for $x=-1$, $f(x) = 0$, this will give another equation on $a$ and $b$.
Can you write down the equations and solve the system or do you need more help?
Edit: The equations will be:
$$begincases
a times 7^4 - 25 times 7^3 + 2 times 7^2+25 times 7 + b = 1296 \
a times (-1)^4 - 25 times (-1)^3 + 2 times (-1)^2+25 times (-1) + b = 0
endcases$$
Edit 2: If you subtract the first equation from the second you get an equation without $b$:
$$a times (7^4-(-1)^4) - 25 times (7^3-(-1)^3) + 2 times (7^2-(-1)^2) + 25 times (7-(-1)) = 1296 .$$
I was a bit lazy and I did not compute the powers of $7$. :)
With this last equation, you'll be able to compute the value of $a$. To obtain the value of $b$ you can use one of the other equations (I suggest using the one with the smaller numbers).
edited Mar 22 at 19:29
answered Mar 22 at 15:28
ErtxiemErtxiem
671112
671112
$begingroup$
this helps could you help me a little more?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:32
$begingroup$
just with the equations
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:40
$begingroup$
still a little confused first time doing this! how do i get the a and b out of this 2 equations? cause a and b are still both in there? i can slove when its one variable but not 2.
$endgroup$
– Enrique Rodriguez
Mar 22 at 16:01
$begingroup$
@EnriqueRodriguez: I added another step in the solution. I believe that you can now compute the final result on your own.
$endgroup$
– Ertxiem
Mar 22 at 19:30
add a comment |
$begingroup$
this helps could you help me a little more?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:32
$begingroup$
just with the equations
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:40
$begingroup$
still a little confused first time doing this! how do i get the a and b out of this 2 equations? cause a and b are still both in there? i can slove when its one variable but not 2.
$endgroup$
– Enrique Rodriguez
Mar 22 at 16:01
$begingroup$
@EnriqueRodriguez: I added another step in the solution. I believe that you can now compute the final result on your own.
$endgroup$
– Ertxiem
Mar 22 at 19:30
$begingroup$
this helps could you help me a little more?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:32
$begingroup$
this helps could you help me a little more?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:32
$begingroup$
just with the equations
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:40
$begingroup$
just with the equations
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:40
$begingroup$
still a little confused first time doing this! how do i get the a and b out of this 2 equations? cause a and b are still both in there? i can slove when its one variable but not 2.
$endgroup$
– Enrique Rodriguez
Mar 22 at 16:01
$begingroup$
still a little confused first time doing this! how do i get the a and b out of this 2 equations? cause a and b are still both in there? i can slove when its one variable but not 2.
$endgroup$
– Enrique Rodriguez
Mar 22 at 16:01
$begingroup$
@EnriqueRodriguez: I added another step in the solution. I believe that you can now compute the final result on your own.
$endgroup$
– Ertxiem
Mar 22 at 19:30
$begingroup$
@EnriqueRodriguez: I added another step in the solution. I believe that you can now compute the final result on your own.
$endgroup$
– Ertxiem
Mar 22 at 19:30
add a comment |
3
$begingroup$
Please do not use pictures for critical portions of your post. Pictures may not be legible, cannot be searched and are not view-able to some, such as those who use screen readers.
$endgroup$
– Brian
Mar 22 at 14:32
$begingroup$
Welcome to stackexchange. When you edit the question to ask it directly rather than with a hard to read image, be sure to tell us what you tried and where you are stuck. Please use mathjax: math.meta.stackexchange.com/questions/5020/…
$endgroup$
– Ethan Bolker
Mar 22 at 14:35
$begingroup$
@EnriqueRodriguez Please add the function and your work into your question. If you show your effort appropriately, it is more likely that somebody will also put his/her effort into providing you some help.
$endgroup$
– Ertxiem
Mar 22 at 14:42
$begingroup$
@Ertxiem is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:22
$begingroup$
@Brian i added the function is this better?
$endgroup$
– Enrique Rodriguez
Mar 22 at 15:23