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What's the difference between different approaches to demonstrating closedness (etc.) sets?


Heine-Borel - Finite Intersection equivalence in subspacesCompact subset of a Hausdorff space is closed.What is the difference between open intervals and standard topology on $mathbbR$How to prove any closed set in $mathbbR$ is $G_delta$Limit point definition of a closed set, versus complement of open set definition?Complements on the product topologyShowing a set is closed and show a set is open(if and only if)Consider the sequence $x_n = (7 + (-1)^n/n, -5) inmathbbR^2$. What are the sets of limit points in different topologies?Please, where can I find some good worked examples of compact spaces?The complement of an open set?













0












$begingroup$


What's the difference between different approaches to demonstrating closedness (etc.) sets?



What confuses me that sometimes I for example find showing



complement is open $implies$ the set is closed



easier than some



"take a sequence of elements and show that limit is not in the set"




The problem with this latter approach is that I find that depending on the set it could be difficult to construct such sequence.




Or would you say that these are equivalent in terms of "difficulty"?










share|cite|improve this question











$endgroup$







  • 2




    $begingroup$
    It's hard to know how to answer your question. Mathematical methods apply differently to different mathematical problems. "Closedness" might be demonstrated one way in one problem and a different way in a different problem. Learning the correct way to demonstrate it in a particular problem is part of the job of the mathematician. If you have a question about doing this in a particular problem that's one thing, but as the question is currently posed I don't think it is answerable.
    $endgroup$
    – Lee Mosher
    Mar 22 at 15:36










  • $begingroup$
    Put a concrete example where "could be difficult to construct such sequence".
    $endgroup$
    – Martín-Blas Pérez Pinilla
    Mar 22 at 16:50










  • $begingroup$
    @Martín-BlasPérezPinilla $ n : n in mathbbZ_+$ is closed, but other than noticing that its complement is union of open intervals $(n,n+1)$, then how would one prove that some sequence would not have a limit in this set? I guess one could show that the sequence difference cannot be less than one?
    $endgroup$
    – mavavilj
    Mar 22 at 17:59











  • $begingroup$
    Right. Using that the space is discrete is the essential fact.
    $endgroup$
    – Martín-Blas Pérez Pinilla
    Mar 22 at 21:12










  • $begingroup$
    That "take a sequence of elements" stuff does not always hold.
    $endgroup$
    – William Elliot
    Mar 22 at 23:11















0












$begingroup$


What's the difference between different approaches to demonstrating closedness (etc.) sets?



What confuses me that sometimes I for example find showing



complement is open $implies$ the set is closed



easier than some



"take a sequence of elements and show that limit is not in the set"




The problem with this latter approach is that I find that depending on the set it could be difficult to construct such sequence.




Or would you say that these are equivalent in terms of "difficulty"?










share|cite|improve this question











$endgroup$







  • 2




    $begingroup$
    It's hard to know how to answer your question. Mathematical methods apply differently to different mathematical problems. "Closedness" might be demonstrated one way in one problem and a different way in a different problem. Learning the correct way to demonstrate it in a particular problem is part of the job of the mathematician. If you have a question about doing this in a particular problem that's one thing, but as the question is currently posed I don't think it is answerable.
    $endgroup$
    – Lee Mosher
    Mar 22 at 15:36










  • $begingroup$
    Put a concrete example where "could be difficult to construct such sequence".
    $endgroup$
    – Martín-Blas Pérez Pinilla
    Mar 22 at 16:50










  • $begingroup$
    @Martín-BlasPérezPinilla $ n : n in mathbbZ_+$ is closed, but other than noticing that its complement is union of open intervals $(n,n+1)$, then how would one prove that some sequence would not have a limit in this set? I guess one could show that the sequence difference cannot be less than one?
    $endgroup$
    – mavavilj
    Mar 22 at 17:59











  • $begingroup$
    Right. Using that the space is discrete is the essential fact.
    $endgroup$
    – Martín-Blas Pérez Pinilla
    Mar 22 at 21:12










  • $begingroup$
    That "take a sequence of elements" stuff does not always hold.
    $endgroup$
    – William Elliot
    Mar 22 at 23:11













0












0








0





$begingroup$


What's the difference between different approaches to demonstrating closedness (etc.) sets?



What confuses me that sometimes I for example find showing



complement is open $implies$ the set is closed



easier than some



"take a sequence of elements and show that limit is not in the set"




The problem with this latter approach is that I find that depending on the set it could be difficult to construct such sequence.




Or would you say that these are equivalent in terms of "difficulty"?










share|cite|improve this question











$endgroup$




What's the difference between different approaches to demonstrating closedness (etc.) sets?



What confuses me that sometimes I for example find showing



complement is open $implies$ the set is closed



easier than some



"take a sequence of elements and show that limit is not in the set"




The problem with this latter approach is that I find that depending on the set it could be difficult to construct such sequence.




Or would you say that these are equivalent in terms of "difficulty"?







general-topology






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 22 at 23:57







mavavilj

















asked Mar 22 at 15:20









mavaviljmavavilj

2,85911138




2,85911138







  • 2




    $begingroup$
    It's hard to know how to answer your question. Mathematical methods apply differently to different mathematical problems. "Closedness" might be demonstrated one way in one problem and a different way in a different problem. Learning the correct way to demonstrate it in a particular problem is part of the job of the mathematician. If you have a question about doing this in a particular problem that's one thing, but as the question is currently posed I don't think it is answerable.
    $endgroup$
    – Lee Mosher
    Mar 22 at 15:36










  • $begingroup$
    Put a concrete example where "could be difficult to construct such sequence".
    $endgroup$
    – Martín-Blas Pérez Pinilla
    Mar 22 at 16:50










  • $begingroup$
    @Martín-BlasPérezPinilla $ n : n in mathbbZ_+$ is closed, but other than noticing that its complement is union of open intervals $(n,n+1)$, then how would one prove that some sequence would not have a limit in this set? I guess one could show that the sequence difference cannot be less than one?
    $endgroup$
    – mavavilj
    Mar 22 at 17:59











  • $begingroup$
    Right. Using that the space is discrete is the essential fact.
    $endgroup$
    – Martín-Blas Pérez Pinilla
    Mar 22 at 21:12










  • $begingroup$
    That "take a sequence of elements" stuff does not always hold.
    $endgroup$
    – William Elliot
    Mar 22 at 23:11












  • 2




    $begingroup$
    It's hard to know how to answer your question. Mathematical methods apply differently to different mathematical problems. "Closedness" might be demonstrated one way in one problem and a different way in a different problem. Learning the correct way to demonstrate it in a particular problem is part of the job of the mathematician. If you have a question about doing this in a particular problem that's one thing, but as the question is currently posed I don't think it is answerable.
    $endgroup$
    – Lee Mosher
    Mar 22 at 15:36










  • $begingroup$
    Put a concrete example where "could be difficult to construct such sequence".
    $endgroup$
    – Martín-Blas Pérez Pinilla
    Mar 22 at 16:50










  • $begingroup$
    @Martín-BlasPérezPinilla $ n : n in mathbbZ_+$ is closed, but other than noticing that its complement is union of open intervals $(n,n+1)$, then how would one prove that some sequence would not have a limit in this set? I guess one could show that the sequence difference cannot be less than one?
    $endgroup$
    – mavavilj
    Mar 22 at 17:59











  • $begingroup$
    Right. Using that the space is discrete is the essential fact.
    $endgroup$
    – Martín-Blas Pérez Pinilla
    Mar 22 at 21:12










  • $begingroup$
    That "take a sequence of elements" stuff does not always hold.
    $endgroup$
    – William Elliot
    Mar 22 at 23:11







2




2




$begingroup$
It's hard to know how to answer your question. Mathematical methods apply differently to different mathematical problems. "Closedness" might be demonstrated one way in one problem and a different way in a different problem. Learning the correct way to demonstrate it in a particular problem is part of the job of the mathematician. If you have a question about doing this in a particular problem that's one thing, but as the question is currently posed I don't think it is answerable.
$endgroup$
– Lee Mosher
Mar 22 at 15:36




$begingroup$
It's hard to know how to answer your question. Mathematical methods apply differently to different mathematical problems. "Closedness" might be demonstrated one way in one problem and a different way in a different problem. Learning the correct way to demonstrate it in a particular problem is part of the job of the mathematician. If you have a question about doing this in a particular problem that's one thing, but as the question is currently posed I don't think it is answerable.
$endgroup$
– Lee Mosher
Mar 22 at 15:36












$begingroup$
Put a concrete example where "could be difficult to construct such sequence".
$endgroup$
– Martín-Blas Pérez Pinilla
Mar 22 at 16:50




$begingroup$
Put a concrete example where "could be difficult to construct such sequence".
$endgroup$
– Martín-Blas Pérez Pinilla
Mar 22 at 16:50












$begingroup$
@Martín-BlasPérezPinilla $ n : n in mathbbZ_+$ is closed, but other than noticing that its complement is union of open intervals $(n,n+1)$, then how would one prove that some sequence would not have a limit in this set? I guess one could show that the sequence difference cannot be less than one?
$endgroup$
– mavavilj
Mar 22 at 17:59





$begingroup$
@Martín-BlasPérezPinilla $ n : n in mathbbZ_+$ is closed, but other than noticing that its complement is union of open intervals $(n,n+1)$, then how would one prove that some sequence would not have a limit in this set? I guess one could show that the sequence difference cannot be less than one?
$endgroup$
– mavavilj
Mar 22 at 17:59













$begingroup$
Right. Using that the space is discrete is the essential fact.
$endgroup$
– Martín-Blas Pérez Pinilla
Mar 22 at 21:12




$begingroup$
Right. Using that the space is discrete is the essential fact.
$endgroup$
– Martín-Blas Pérez Pinilla
Mar 22 at 21:12












$begingroup$
That "take a sequence of elements" stuff does not always hold.
$endgroup$
– William Elliot
Mar 22 at 23:11




$begingroup$
That "take a sequence of elements" stuff does not always hold.
$endgroup$
– William Elliot
Mar 22 at 23:11










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