Proving infeasibility using DualityQuestions about weak duality theoremStrong duality theorem written with iffs?linear programming infeasibility, dual & primal relationUtilizing theorems of duality to solve primal linear programming problemStrong duality optimal controlFeasibility and boundedness of non-linear programmingHow obtain the dual variables' value given a primal solutionFarkas Lemma using dualityMeasuring infeasibility in convex optimization, relations with dual problemdoes strong duality hold for minimum cost flow problem
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Proving infeasibility using Duality
Questions about weak duality theoremStrong duality theorem written with iffs?linear programming infeasibility, dual & primal relationUtilizing theorems of duality to solve primal linear programming problemStrong duality optimal controlFeasibility and boundedness of non-linear programmingHow obtain the dual variables' value given a primal solutionFarkas Lemma using dualityMeasuring infeasibility in convex optimization, relations with dual problemdoes strong duality hold for minimum cost flow problem
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suppose we have the linear program min$c^Tx: Ax leq 0, x leq 0$ and its corresponding dual
max$0^Tx: A^Ty geq 0, y leq 0$. How can we show that the Dual is infeasible? I started by contradiction and assumed the Dual is feasible, then its optimal value will be $0$ and by strong duality, the primal should also have an optimal value of $0$, however I am not able to reach a contradiction from this point.
linear-algebra linear-programming duality-theorems
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add a comment |
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suppose we have the linear program min$c^Tx: Ax leq 0, x leq 0$ and its corresponding dual
max$0^Tx: A^Ty geq 0, y leq 0$. How can we show that the Dual is infeasible? I started by contradiction and assumed the Dual is feasible, then its optimal value will be $0$ and by strong duality, the primal should also have an optimal value of $0$, however I am not able to reach a contradiction from this point.
linear-algebra linear-programming duality-theorems
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add a comment |
$begingroup$
suppose we have the linear program min$c^Tx: Ax leq 0, x leq 0$ and its corresponding dual
max$0^Tx: A^Ty geq 0, y leq 0$. How can we show that the Dual is infeasible? I started by contradiction and assumed the Dual is feasible, then its optimal value will be $0$ and by strong duality, the primal should also have an optimal value of $0$, however I am not able to reach a contradiction from this point.
linear-algebra linear-programming duality-theorems
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suppose we have the linear program min$c^Tx: Ax leq 0, x leq 0$ and its corresponding dual
max$0^Tx: A^Ty geq 0, y leq 0$. How can we show that the Dual is infeasible? I started by contradiction and assumed the Dual is feasible, then its optimal value will be $0$ and by strong duality, the primal should also have an optimal value of $0$, however I am not able to reach a contradiction from this point.
linear-algebra linear-programming duality-theorems
linear-algebra linear-programming duality-theorems
asked Mar 20 at 19:58
SkrrrrrttttSkrrrrrtttt
387110
387110
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1 Answer
1
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Hint
The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?
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I am not familiar with this way of applying duality
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– Skrrrrrtttt
Mar 20 at 20:34
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Hint
The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?
$endgroup$
$begingroup$
I am not familiar with this way of applying duality
$endgroup$
– Skrrrrrtttt
Mar 20 at 20:34
add a comment |
$begingroup$
Hint
The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?
$endgroup$
$begingroup$
I am not familiar with this way of applying duality
$endgroup$
– Skrrrrrtttt
Mar 20 at 20:34
add a comment |
$begingroup$
Hint
The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?
$endgroup$
Hint
The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?
answered Mar 20 at 20:26
Mostafa AyazMostafa Ayaz
18.2k31040
18.2k31040
$begingroup$
I am not familiar with this way of applying duality
$endgroup$
– Skrrrrrtttt
Mar 20 at 20:34
add a comment |
$begingroup$
I am not familiar with this way of applying duality
$endgroup$
– Skrrrrrtttt
Mar 20 at 20:34
$begingroup$
I am not familiar with this way of applying duality
$endgroup$
– Skrrrrrtttt
Mar 20 at 20:34
$begingroup$
I am not familiar with this way of applying duality
$endgroup$
– Skrrrrrtttt
Mar 20 at 20:34
add a comment |
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