Proving infeasibility using DualityQuestions about weak duality theoremStrong duality theorem written with iffs?linear programming infeasibility, dual & primal relationUtilizing theorems of duality to solve primal linear programming problemStrong duality optimal controlFeasibility and boundedness of non-linear programmingHow obtain the dual variables' value given a primal solutionFarkas Lemma using dualityMeasuring infeasibility in convex optimization, relations with dual problemdoes strong duality hold for minimum cost flow problem

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Proving infeasibility using Duality


Questions about weak duality theoremStrong duality theorem written with iffs?linear programming infeasibility, dual & primal relationUtilizing theorems of duality to solve primal linear programming problemStrong duality optimal controlFeasibility and boundedness of non-linear programmingHow obtain the dual variables' value given a primal solutionFarkas Lemma using dualityMeasuring infeasibility in convex optimization, relations with dual problemdoes strong duality hold for minimum cost flow problem













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$begingroup$


suppose we have the linear program min$c^Tx: Ax leq 0, x leq 0$ and its corresponding dual



max$0^Tx: A^Ty geq 0, y leq 0$. How can we show that the Dual is infeasible? I started by contradiction and assumed the Dual is feasible, then its optimal value will be $0$ and by strong duality, the primal should also have an optimal value of $0$, however I am not able to reach a contradiction from this point.










share|cite|improve this question









$endgroup$
















    0












    $begingroup$


    suppose we have the linear program min$c^Tx: Ax leq 0, x leq 0$ and its corresponding dual



    max$0^Tx: A^Ty geq 0, y leq 0$. How can we show that the Dual is infeasible? I started by contradiction and assumed the Dual is feasible, then its optimal value will be $0$ and by strong duality, the primal should also have an optimal value of $0$, however I am not able to reach a contradiction from this point.










    share|cite|improve this question









    $endgroup$














      0












      0








      0





      $begingroup$


      suppose we have the linear program min$c^Tx: Ax leq 0, x leq 0$ and its corresponding dual



      max$0^Tx: A^Ty geq 0, y leq 0$. How can we show that the Dual is infeasible? I started by contradiction and assumed the Dual is feasible, then its optimal value will be $0$ and by strong duality, the primal should also have an optimal value of $0$, however I am not able to reach a contradiction from this point.










      share|cite|improve this question









      $endgroup$




      suppose we have the linear program min$c^Tx: Ax leq 0, x leq 0$ and its corresponding dual



      max$0^Tx: A^Ty geq 0, y leq 0$. How can we show that the Dual is infeasible? I started by contradiction and assumed the Dual is feasible, then its optimal value will be $0$ and by strong duality, the primal should also have an optimal value of $0$, however I am not able to reach a contradiction from this point.







      linear-algebra linear-programming duality-theorems






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      asked Mar 20 at 19:58









      SkrrrrrttttSkrrrrrtttt

      387110




      387110




















          1 Answer
          1






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          0












          $begingroup$

          Hint



          The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            I am not familiar with this way of applying duality
            $endgroup$
            – Skrrrrrtttt
            Mar 20 at 20:34











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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

          votes









          0












          $begingroup$

          Hint



          The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            I am not familiar with this way of applying duality
            $endgroup$
            – Skrrrrrtttt
            Mar 20 at 20:34















          0












          $begingroup$

          Hint



          The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            I am not familiar with this way of applying duality
            $endgroup$
            – Skrrrrrtttt
            Mar 20 at 20:34













          0












          0








          0





          $begingroup$

          Hint



          The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?






          share|cite|improve this answer









          $endgroup$



          Hint



          The dual for this problem is $$max g(lambda_1,lambda_2)\texts. t.\lambda_1,lambda_2succeq 0$$where $$g(lambda_1,lambda_2)=inf_xc^Tx+lambda_1^TAx+lambda_2^Tx\=inf_x(c+A^Tlambda_1+lambda_2)^Tx$$Now, when is the dual problem infeasible? How is it applied here?







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Mar 20 at 20:26









          Mostafa AyazMostafa Ayaz

          18.2k31040




          18.2k31040











          • $begingroup$
            I am not familiar with this way of applying duality
            $endgroup$
            – Skrrrrrtttt
            Mar 20 at 20:34
















          • $begingroup$
            I am not familiar with this way of applying duality
            $endgroup$
            – Skrrrrrtttt
            Mar 20 at 20:34















          $begingroup$
          I am not familiar with this way of applying duality
          $endgroup$
          – Skrrrrrtttt
          Mar 20 at 20:34




          $begingroup$
          I am not familiar with this way of applying duality
          $endgroup$
          – Skrrrrrtttt
          Mar 20 at 20:34

















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