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Does a $kappa$-Kurepa tree imply we have a slim $kappa$-Kurepa tree?


The tree property for non-weakly compact $kappa$IF $kappa$ is weakly compact, then $kappa$ has the tree property.Tree, no uncountable antichainsViewing a $kappa$-tree as a set of functions.How can an $omega_1$-tree possibly be normal and yet not have any $omega_1$-branch?Kurepa trees and inaccessible cardinals in $L$For which $kappa$ can we have if $#alpha=#beta=kappa$, then the following also have cardinality $kappa$?Definition for “power” of a tree? (Kurepa trees)existence of a branch of length $kappa$ in a tree of height $kappa$ whose levels are finite$kappa^+$ tree with no $kappa^+$ branch













3












$begingroup$


Take a $kappa$-Kurepa tree to be a tree with more than $kappa$ branches, of height $kappa$, each level having cardinality less than $kappa$



A slim $kappa$-Kurepa tree is the same but the cardinality of each level $alpha<kappa$ has cardinality $leq|alpha|$.



Is it true in general the existence of a $kappa$-Kurepa tree implies a slim one exists?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    What are your thoughts on the problem? What have you tried?
    $endgroup$
    – clathratus
    Mar 20 at 20:02






  • 2




    $begingroup$
    @clathratus: The question is one that is sufficiently advanced that your comment, although well-meaning, feels to me a bit out of touch.
    $endgroup$
    – Asaf Karagila
    Mar 20 at 23:35















3












$begingroup$


Take a $kappa$-Kurepa tree to be a tree with more than $kappa$ branches, of height $kappa$, each level having cardinality less than $kappa$



A slim $kappa$-Kurepa tree is the same but the cardinality of each level $alpha<kappa$ has cardinality $leq|alpha|$.



Is it true in general the existence of a $kappa$-Kurepa tree implies a slim one exists?










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    What are your thoughts on the problem? What have you tried?
    $endgroup$
    – clathratus
    Mar 20 at 20:02






  • 2




    $begingroup$
    @clathratus: The question is one that is sufficiently advanced that your comment, although well-meaning, feels to me a bit out of touch.
    $endgroup$
    – Asaf Karagila
    Mar 20 at 23:35













3












3








3





$begingroup$


Take a $kappa$-Kurepa tree to be a tree with more than $kappa$ branches, of height $kappa$, each level having cardinality less than $kappa$



A slim $kappa$-Kurepa tree is the same but the cardinality of each level $alpha<kappa$ has cardinality $leq|alpha|$.



Is it true in general the existence of a $kappa$-Kurepa tree implies a slim one exists?










share|cite|improve this question









$endgroup$




Take a $kappa$-Kurepa tree to be a tree with more than $kappa$ branches, of height $kappa$, each level having cardinality less than $kappa$



A slim $kappa$-Kurepa tree is the same but the cardinality of each level $alpha<kappa$ has cardinality $leq|alpha|$.



Is it true in general the existence of a $kappa$-Kurepa tree implies a slim one exists?







set-theory






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 20 at 19:26









A.HA.H

184




184







  • 1




    $begingroup$
    What are your thoughts on the problem? What have you tried?
    $endgroup$
    – clathratus
    Mar 20 at 20:02






  • 2




    $begingroup$
    @clathratus: The question is one that is sufficiently advanced that your comment, although well-meaning, feels to me a bit out of touch.
    $endgroup$
    – Asaf Karagila
    Mar 20 at 23:35












  • 1




    $begingroup$
    What are your thoughts on the problem? What have you tried?
    $endgroup$
    – clathratus
    Mar 20 at 20:02






  • 2




    $begingroup$
    @clathratus: The question is one that is sufficiently advanced that your comment, although well-meaning, feels to me a bit out of touch.
    $endgroup$
    – Asaf Karagila
    Mar 20 at 23:35







1




1




$begingroup$
What are your thoughts on the problem? What have you tried?
$endgroup$
– clathratus
Mar 20 at 20:02




$begingroup$
What are your thoughts on the problem? What have you tried?
$endgroup$
– clathratus
Mar 20 at 20:02




2




2




$begingroup$
@clathratus: The question is one that is sufficiently advanced that your comment, although well-meaning, feels to me a bit out of touch.
$endgroup$
– Asaf Karagila
Mar 20 at 23:35




$begingroup$
@clathratus: The question is one that is sufficiently advanced that your comment, although well-meaning, feels to me a bit out of touch.
$endgroup$
– Asaf Karagila
Mar 20 at 23:35










1 Answer
1






active

oldest

votes


















2












$begingroup$

Well, if $kappa$ is a successor, then any $kappa$-Kurepa tree is slim (or, at least, is slim above some level).



But the implication is not true in general. For example, if $kappa$ is a strong limit, then the full binary tree of height $kappa$ is a $kappa$-Kurepa tree. But if $kappa$ additionally has some compactness properties (for example, if it is measurable) then there cannot be any slim $kappa$-Kurepa trees.






share|cite|improve this answer









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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2












    $begingroup$

    Well, if $kappa$ is a successor, then any $kappa$-Kurepa tree is slim (or, at least, is slim above some level).



    But the implication is not true in general. For example, if $kappa$ is a strong limit, then the full binary tree of height $kappa$ is a $kappa$-Kurepa tree. But if $kappa$ additionally has some compactness properties (for example, if it is measurable) then there cannot be any slim $kappa$-Kurepa trees.






    share|cite|improve this answer









    $endgroup$

















      2












      $begingroup$

      Well, if $kappa$ is a successor, then any $kappa$-Kurepa tree is slim (or, at least, is slim above some level).



      But the implication is not true in general. For example, if $kappa$ is a strong limit, then the full binary tree of height $kappa$ is a $kappa$-Kurepa tree. But if $kappa$ additionally has some compactness properties (for example, if it is measurable) then there cannot be any slim $kappa$-Kurepa trees.






      share|cite|improve this answer









      $endgroup$















        2












        2








        2





        $begingroup$

        Well, if $kappa$ is a successor, then any $kappa$-Kurepa tree is slim (or, at least, is slim above some level).



        But the implication is not true in general. For example, if $kappa$ is a strong limit, then the full binary tree of height $kappa$ is a $kappa$-Kurepa tree. But if $kappa$ additionally has some compactness properties (for example, if it is measurable) then there cannot be any slim $kappa$-Kurepa trees.






        share|cite|improve this answer









        $endgroup$



        Well, if $kappa$ is a successor, then any $kappa$-Kurepa tree is slim (or, at least, is slim above some level).



        But the implication is not true in general. For example, if $kappa$ is a strong limit, then the full binary tree of height $kappa$ is a $kappa$-Kurepa tree. But if $kappa$ additionally has some compactness properties (for example, if it is measurable) then there cannot be any slim $kappa$-Kurepa trees.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Mar 21 at 16:12









        Miha HabičMiha Habič

        5,66511744




        5,66511744



























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