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How is solve If A and B are similar n a matrices, then show that A and B have the same characteristic equation and therefore have the same eigenvalues [closed]

-1

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If A and B are similar n a matrices, then show that A and B have the same characteristic equation and therefore have the same eigenvalues.

matrices eigenvalues-eigenvectors characteristics

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asked Mar 20 at 11:05

Tharindu LakshanTharindu Lakshan

1

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closed as off-topic by Gerry Myerson, mrtaurho, Paul Frost, José Carlos Santos, rtybase Mar 24 at 19:09

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – mrtaurho, Paul Frost, rtybase

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  If $f$ is a polynomial, then $P^-1f(A)P=f(P^-1AP)$.
  $endgroup$
  – Gerry Myerson
  Mar 20 at 12:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Did that help, Tharindu?
  $endgroup$
  – Gerry Myerson
  Mar 21 at 22:35
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I'm voting to close this question as off-topic because OP has abandoned it.
  $endgroup$
  – Gerry Myerson
  Mar 24 at 8:49
  

  
  
  
  

add a comment | 

-1

$begingroup$

If A and B are similar n a matrices, then show that A and B have the same characteristic equation and therefore have the same eigenvalues.

matrices eigenvalues-eigenvectors characteristics

share|cite|improve this question

asked Mar 20 at 11:05

Tharindu LakshanTharindu Lakshan

1

$endgroup$

closed as off-topic by Gerry Myerson, mrtaurho, Paul Frost, José Carlos Santos, rtybase Mar 24 at 19:09

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – mrtaurho, Paul Frost, rtybase

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  If $f$ is a polynomial, then $P^-1f(A)P=f(P^-1AP)$.
  $endgroup$
  – Gerry Myerson
  Mar 20 at 12:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Did that help, Tharindu?
  $endgroup$
  – Gerry Myerson
  Mar 21 at 22:35
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  I'm voting to close this question as off-topic because OP has abandoned it.
  $endgroup$
  – Gerry Myerson
  Mar 24 at 8:49
  

  
  
  
  

add a comment | 

$begingroup$

If A and B are similar n a matrices, then show that A and B have the same characteristic equation and therefore have the same eigenvalues.

matrices eigenvalues-eigenvectors characteristics

share|cite|improve this question

asked Mar 20 at 11:05

Tharindu LakshanTharindu Lakshan

1

$endgroup$

share|cite|improve this question

asked Mar 20 at 11:05

Tharindu LakshanTharindu Lakshan

1

share|cite|improve this question

asked Mar 20 at 11:05

Tharindu LakshanTharindu Lakshan

1

asked Mar 20 at 11:05

Tharindu LakshanTharindu Lakshan

1

asked Mar 20 at 11:05

Tharindu LakshanTharindu Lakshan

1