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Expand logical conjugation expression
Writing an expression using logicBasic logical math propertiesLogical Expression and truth tableExpanding a logical expressionHelp with proving a logical equivalenceHow to simplify this logical expression?Translate Expression Into Logical SymbolismHow can I convert logic expression from DNF to CNF or CNF to DNF?Need help simplifying this Boolean expressionSquare brackets in logical expression
$begingroup$
I want to expand following expression.
$$(A land B)$$
where
$$
beginarraycc
A =& (1-a) b c \
B =& (1-c) a b \
endarray
$$
Thanks in advance.
logic
asked Mar 6 at 10:43
Hasitha PereraHasitha Perera
11
$endgroup$
add a comment |
$begingroup$
I want to expand following expression.
$$(A land B)$$
where
$$
beginarraycc
A =& (1-a) b c \
B =& (1-c) a b \
endarray
$$
Thanks in advance.
logic
asked Mar 6 at 10:43
Hasitha PereraHasitha Perera
11
$endgroup$
$begingroup$
Please, copy-paste the formulas into the text of the question.
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 10:44
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Mar 6 at 10:48
$begingroup$
Expand what ? You have to formulas and you have to write their conjunction ?
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 14:43
$begingroup$
Can we write above formula as follows A∧B = (bc-abc)∧(ab-abc) = bc∧ab-bc∧abc-abc∧ab+abc∧abc
$endgroup$
– Hasitha Perera
Mar 13 at 10:12
add a comment |
$begingroup$
I want to expand following expression.
$$(A land B)$$
where
$$
beginarraycc
A =& (1-a) b c \
B =& (1-c) a b \
endarray
$$
Thanks in advance.
logic
asked Mar 6 at 10:43
Hasitha PereraHasitha Perera
11
$endgroup$
I want to expand following expression.
$$(A land B)$$
where
$$
beginarraycc
A =& (1-a) b c \
B =& (1-c) a b \
endarray
$$
Thanks in advance.
logic
logic
asked Mar 6 at 10:43
Hasitha PereraHasitha Perera
11
asked Mar 6 at 10:43
Hasitha PereraHasitha Perera
11
edited Mar 13 at 10:09
Hasitha Perera
asked Mar 6 at 10:43
Hasitha PereraHasitha Perera
11
asked Mar 6 at 10:43
Hasitha PereraHasitha Perera
11
asked Mar 6 at 10:43
Hasitha PereraHasitha Perera
11
11
$begingroup$
Please, copy-paste the formulas into the text of the question.
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 10:44
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Mar 6 at 10:48
$begingroup$
Expand what ? You have to formulas and you have to write their conjunction ?
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 14:43
$begingroup$
Can we write above formula as follows A∧B = (bc-abc)∧(ab-abc) = bc∧ab-bc∧abc-abc∧ab+abc∧abc
$endgroup$
– Hasitha Perera
Mar 13 at 10:12
add a comment |
$begingroup$
Please, copy-paste the formulas into the text of the question.
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 10:44
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Mar 6 at 10:48
$begingroup$
Expand what ? You have to formulas and you have to write their conjunction ?
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 14:43
$begingroup$
Can we write above formula as follows A∧B = (bc-abc)∧(ab-abc) = bc∧ab-bc∧abc-abc∧ab+abc∧abc
$endgroup$
– Hasitha Perera
Mar 13 at 10:12
$begingroup$
Please, copy-paste the formulas into the text of the question.
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 10:44
$begingroup$
Please, copy-paste the formulas into the text of the question.
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 10:44
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Mar 6 at 10:48
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Mar 6 at 10:48
$begingroup$
Expand what ? You have to formulas and you have to write their conjunction ?
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 14:43
$begingroup$
Expand what ? You have to formulas and you have to write their conjunction ?
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 14:43
$begingroup$
Can we write above formula as follows A∧B = (bc-abc)∧(ab-abc) = bc∧ab-bc∧abc-abc∧ab+abc∧abc
$endgroup$
– Hasitha Perera
Mar 13 at 10:12
$begingroup$
Can we write above formula as follows A∧B = (bc-abc)∧(ab-abc) = bc∧ab-bc∧abc-abc∧ab+abc∧abc
$endgroup$
– Hasitha Perera
Mar 13 at 10:12
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Let's define $u'=1-u$ therefore $$Aland B=a'bcland abc'=a'land aland bland c'land c=0$$
answered Mar 13 at 12:00
Mostafa AyazMostafa Ayaz
16.5k3939
$endgroup$
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
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oldest
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oldest
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oldest
votes
$begingroup$
Let's define $u'=1-u$ therefore $$Aland B=a'bcland abc'=a'land aland bland c'land c=0$$
answered Mar 13 at 12:00
Mostafa AyazMostafa Ayaz
16.5k3939
$endgroup$
add a comment |
$begingroup$
Let's define $u'=1-u$ therefore $$Aland B=a'bcland abc'=a'land aland bland c'land c=0$$
answered Mar 13 at 12:00
Mostafa AyazMostafa Ayaz
16.5k3939
$endgroup$
add a comment |
$begingroup$
Let's define $u'=1-u$ therefore $$Aland B=a'bcland abc'=a'land aland bland c'land c=0$$
answered Mar 13 at 12:00
Mostafa AyazMostafa Ayaz
16.5k3939
$endgroup$
Let's define $u'=1-u$ therefore $$Aland B=a'bcland abc'=a'land aland bland c'land c=0$$
answered Mar 13 at 12:00
Mostafa AyazMostafa Ayaz
16.5k3939
answered Mar 13 at 12:00
Mostafa AyazMostafa Ayaz
16.5k3939
answered Mar 13 at 12:00
Mostafa AyazMostafa Ayaz
16.5k3939
answered Mar 13 at 12:00
Mostafa AyazMostafa Ayaz
16.5k3939
16.5k3939
add a comment |
add a comment |
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$begingroup$
Please, copy-paste the formulas into the text of the question.
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 10:44
$begingroup$
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
$endgroup$
– José Carlos Santos
Mar 6 at 10:48
$begingroup$
Expand what ? You have to formulas and you have to write their conjunction ?
$endgroup$
– Mauro ALLEGRANZA
Mar 6 at 14:43
$begingroup$
Can we write above formula as follows A∧B = (bc-abc)∧(ab-abc) = bc∧ab-bc∧abc-abc∧ab+abc∧abc
$endgroup$
– Hasitha Perera
Mar 13 at 10:12