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Solving Non-Linear First order ODEs


First order non linear Ordinary differential equationsSolving first order non linear ODEA second order linear ordinary differential equationFirst order non-linear differential equationSolving first order non linear equationSolving non-linear second order ODEsNon linear first order ODE, not exact and not separableSolving non-linear ODEsSolving Higher Order Partial Differential EquationIs this an exact differential equation or a first order non-linear ordinary differential equation?













1












$begingroup$


The equation is:
$$fracdxdt = beta + alphax(1 - fracxkappa) - x(mu + nu + delta)$$



$beta, alpha, kappa, mu, nu, delta$ are all constants.
I am trying to solve this differential equation.



I understand that this is a non-linear, first order differential equation, however it is non-separable due to the logistic component.
I don't think it is exact either so I don't know what to do now.



Any help would be appreciated.










share|cite|improve this question







New contributor




Emma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







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  • $begingroup$
    Am I right to say that it takes the form of a Riccati differential equation if the logistic component is expanded out? Is there a technique used to solve Riccati differential equations?
    $endgroup$
    – Emma
    Mar 13 at 11:03















1












$begingroup$


The equation is:
$$fracdxdt = beta + alphax(1 - fracxkappa) - x(mu + nu + delta)$$



$beta, alpha, kappa, mu, nu, delta$ are all constants.
I am trying to solve this differential equation.



I understand that this is a non-linear, first order differential equation, however it is non-separable due to the logistic component.
I don't think it is exact either so I don't know what to do now.



Any help would be appreciated.










share|cite|improve this question







New contributor




Emma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Am I right to say that it takes the form of a Riccati differential equation if the logistic component is expanded out? Is there a technique used to solve Riccati differential equations?
    $endgroup$
    – Emma
    Mar 13 at 11:03













1












1








1





$begingroup$


The equation is:
$$fracdxdt = beta + alphax(1 - fracxkappa) - x(mu + nu + delta)$$



$beta, alpha, kappa, mu, nu, delta$ are all constants.
I am trying to solve this differential equation.



I understand that this is a non-linear, first order differential equation, however it is non-separable due to the logistic component.
I don't think it is exact either so I don't know what to do now.



Any help would be appreciated.










share|cite|improve this question







New contributor




Emma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




The equation is:
$$fracdxdt = beta + alphax(1 - fracxkappa) - x(mu + nu + delta)$$



$beta, alpha, kappa, mu, nu, delta$ are all constants.
I am trying to solve this differential equation.



I understand that this is a non-linear, first order differential equation, however it is non-separable due to the logistic component.
I don't think it is exact either so I don't know what to do now.



Any help would be appreciated.







ordinary-differential-equations






share|cite|improve this question







New contributor




Emma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question







New contributor




Emma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question






New contributor




Emma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Mar 13 at 10:44









EmmaEmma

274




274




New contributor




Emma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





Emma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Emma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    Am I right to say that it takes the form of a Riccati differential equation if the logistic component is expanded out? Is there a technique used to solve Riccati differential equations?
    $endgroup$
    – Emma
    Mar 13 at 11:03
















  • $begingroup$
    Am I right to say that it takes the form of a Riccati differential equation if the logistic component is expanded out? Is there a technique used to solve Riccati differential equations?
    $endgroup$
    – Emma
    Mar 13 at 11:03















$begingroup$
Am I right to say that it takes the form of a Riccati differential equation if the logistic component is expanded out? Is there a technique used to solve Riccati differential equations?
$endgroup$
– Emma
Mar 13 at 11:03




$begingroup$
Am I right to say that it takes the form of a Riccati differential equation if the logistic component is expanded out? Is there a technique used to solve Riccati differential equations?
$endgroup$
– Emma
Mar 13 at 11:03










1 Answer
1






active

oldest

votes


















0












$begingroup$

The equation is nonlinear, but it is separable, as it has the form
$$
fractextd xtextd t = f(x).
$$

Therefore, all you have to do is to solve the equation
$$
int^x frac1f(hatx)textdhatx = t + t_0
$$

for $x$. You will obtain something of the form
$$
x(t) = c_1 + c_2 ,texttanh left(c_3(t+t_0)right),
$$

where $c_1,c_2,c_3$ are constants depending on the model parameters $alpha,beta,delta,kappa,mu,nu$.






share|cite|improve this answer









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    1 Answer
    1






    active

    oldest

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    1 Answer
    1






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

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    0












    $begingroup$

    The equation is nonlinear, but it is separable, as it has the form
    $$
    fractextd xtextd t = f(x).
    $$

    Therefore, all you have to do is to solve the equation
    $$
    int^x frac1f(hatx)textdhatx = t + t_0
    $$

    for $x$. You will obtain something of the form
    $$
    x(t) = c_1 + c_2 ,texttanh left(c_3(t+t_0)right),
    $$

    where $c_1,c_2,c_3$ are constants depending on the model parameters $alpha,beta,delta,kappa,mu,nu$.






    share|cite|improve this answer









    $endgroup$

















      0












      $begingroup$

      The equation is nonlinear, but it is separable, as it has the form
      $$
      fractextd xtextd t = f(x).
      $$

      Therefore, all you have to do is to solve the equation
      $$
      int^x frac1f(hatx)textdhatx = t + t_0
      $$

      for $x$. You will obtain something of the form
      $$
      x(t) = c_1 + c_2 ,texttanh left(c_3(t+t_0)right),
      $$

      where $c_1,c_2,c_3$ are constants depending on the model parameters $alpha,beta,delta,kappa,mu,nu$.






      share|cite|improve this answer









      $endgroup$















        0












        0








        0





        $begingroup$

        The equation is nonlinear, but it is separable, as it has the form
        $$
        fractextd xtextd t = f(x).
        $$

        Therefore, all you have to do is to solve the equation
        $$
        int^x frac1f(hatx)textdhatx = t + t_0
        $$

        for $x$. You will obtain something of the form
        $$
        x(t) = c_1 + c_2 ,texttanh left(c_3(t+t_0)right),
        $$

        where $c_1,c_2,c_3$ are constants depending on the model parameters $alpha,beta,delta,kappa,mu,nu$.






        share|cite|improve this answer









        $endgroup$



        The equation is nonlinear, but it is separable, as it has the form
        $$
        fractextd xtextd t = f(x).
        $$

        Therefore, all you have to do is to solve the equation
        $$
        int^x frac1f(hatx)textdhatx = t + t_0
        $$

        for $x$. You will obtain something of the form
        $$
        x(t) = c_1 + c_2 ,texttanh left(c_3(t+t_0)right),
        $$

        where $c_1,c_2,c_3$ are constants depending on the model parameters $alpha,beta,delta,kappa,mu,nu$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Mar 13 at 11:17









        Frits VeermanFrits Veerman

        7,0312921




        7,0312921




















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