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An Accountant Seeks the Help of a Mathematician


Four prisoners wearing black and white hatsDeduce the numbers (addition + subtraction)Determine $X$ and $Y$: sum, difference and ratioSum, Product and DifferenceFind the identity of the four troll brothers4 Gridded Prime NumbersHow does the hit-man assassinate his target using only two questions?My Friend, 4 kids and gold and silver coinsA Counterfeit $100 Bill among 93 BillsRanking teacher salaries in the Republic of al'Alghaz













7












$begingroup$


The accountant complaints to the mathematician:




“I lent money to five other faculty members and still haven’t been paid back. You are one of them; the other four owe me 12 dollars altogether, but I don’t remember how much each person owes me separately.”



“Are the debts in whole dollars?”



“Yes. I do remember that the four other debts multiplied together equals your debt. Do you remember how much you owe me?”



“Yes, but I still haven’t figured out how much each of the other four owe you.”



“Wait! The statistician is the one who owes the least.”



“That does it. Now I know the amount of each debt.”




What are the debts and how did the mathematician determine them?










share|improve this question











$endgroup$
















    7












    $begingroup$


    The accountant complaints to the mathematician:




    “I lent money to five other faculty members and still haven’t been paid back. You are one of them; the other four owe me 12 dollars altogether, but I don’t remember how much each person owes me separately.”



    “Are the debts in whole dollars?”



    “Yes. I do remember that the four other debts multiplied together equals your debt. Do you remember how much you owe me?”



    “Yes, but I still haven’t figured out how much each of the other four owe you.”



    “Wait! The statistician is the one who owes the least.”



    “That does it. Now I know the amount of each debt.”




    What are the debts and how did the mathematician determine them?










    share|improve this question











    $endgroup$














      7












      7








      7





      $begingroup$


      The accountant complaints to the mathematician:




      “I lent money to five other faculty members and still haven’t been paid back. You are one of them; the other four owe me 12 dollars altogether, but I don’t remember how much each person owes me separately.”



      “Are the debts in whole dollars?”



      “Yes. I do remember that the four other debts multiplied together equals your debt. Do you remember how much you owe me?”



      “Yes, but I still haven’t figured out how much each of the other four owe you.”



      “Wait! The statistician is the one who owes the least.”



      “That does it. Now I know the amount of each debt.”




      What are the debts and how did the mathematician determine them?










      share|improve this question











      $endgroup$




      The accountant complaints to the mathematician:




      “I lent money to five other faculty members and still haven’t been paid back. You are one of them; the other four owe me 12 dollars altogether, but I don’t remember how much each person owes me separately.”



      “Are the debts in whole dollars?”



      “Yes. I do remember that the four other debts multiplied together equals your debt. Do you remember how much you owe me?”



      “Yes, but I still haven’t figured out how much each of the other four owe you.”



      “Wait! The statistician is the one who owes the least.”



      “That does it. Now I know the amount of each debt.”




      What are the debts and how did the mathematician determine them?







      logical-deduction number-theory






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 14 at 15:46









      Hugh

      2,26811127




      2,26811127










      asked Mar 14 at 15:32









      user13242352user13242352

      443




      443




















          2 Answers
          2






          active

          oldest

          votes


















          15












          $begingroup$

          The mathematician owes




          48 dollars




          and the other faculty members owe




          4, 4, 3 and 1 dollar.




          Explanation:




          We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




          Table:




          9 + 1 + 1 + 1 = 12 --> 9
          8 + 2 + 1 + 1 = 12 --> 16
          7 + 3 + 1 + 1 = 12 --> 21
          7 + 2 + 2 + 1 = 12 --> 28
          6 + 4 + 1 + 1 = 12 --> 24
          6 + 3 + 2 + 1 = 12 --> 36
          6 + 2 + 2 + 2 = 12 --> 48
          5 + 5 + 1 + 1 = 12 --> 25
          5 + 4 + 2 + 1 = 12 --> 40
          5 + 3 + 3 + 1 = 12 --> 45
          5 + 3 + 2 + 2 = 12 --> 60
          4 + 4 + 3 + 1 = 12 --> 48
          4 + 4 + 2 + 2 = 12 --> 64
          4 + 3 + 3 + 2 = 12 --> 72
          3 + 3 + 3 + 3 = 12 --> 81

          Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.







          share|improve this answer











          $endgroup$








          • 3




            $begingroup$
            Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
            $endgroup$
            – Kevin
            Mar 14 at 16:57


















          5












          $begingroup$

          The mathematician owes




          $48




          Because




          nothing is said that the individual debts are unique, only that the lowest one must be.

          So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


          1,2,2,7 → $28

          1,2,3,6 → $36

          1,2,4,5 → $40

          1,3,3,5 → $45

          1,3,4,4 → $48




          Now the mathematician says at first that




          the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


          The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

          The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

          The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

          The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.







          share|improve this answer









          $endgroup$








          • 1




            $begingroup$
            In the second part, I think you are missing the possibility 2,3,3,4
            $endgroup$
            – Cain
            Mar 14 at 21:56










          Your Answer





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          2 Answers
          2






          active

          oldest

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          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          15












          $begingroup$

          The mathematician owes




          48 dollars




          and the other faculty members owe




          4, 4, 3 and 1 dollar.




          Explanation:




          We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




          Table:




          9 + 1 + 1 + 1 = 12 --> 9
          8 + 2 + 1 + 1 = 12 --> 16
          7 + 3 + 1 + 1 = 12 --> 21
          7 + 2 + 2 + 1 = 12 --> 28
          6 + 4 + 1 + 1 = 12 --> 24
          6 + 3 + 2 + 1 = 12 --> 36
          6 + 2 + 2 + 2 = 12 --> 48
          5 + 5 + 1 + 1 = 12 --> 25
          5 + 4 + 2 + 1 = 12 --> 40
          5 + 3 + 3 + 1 = 12 --> 45
          5 + 3 + 2 + 2 = 12 --> 60
          4 + 4 + 3 + 1 = 12 --> 48
          4 + 4 + 2 + 2 = 12 --> 64
          4 + 3 + 3 + 2 = 12 --> 72
          3 + 3 + 3 + 3 = 12 --> 81

          Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.







          share|improve this answer











          $endgroup$








          • 3




            $begingroup$
            Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
            $endgroup$
            – Kevin
            Mar 14 at 16:57















          15












          $begingroup$

          The mathematician owes




          48 dollars




          and the other faculty members owe




          4, 4, 3 and 1 dollar.




          Explanation:




          We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




          Table:




          9 + 1 + 1 + 1 = 12 --> 9
          8 + 2 + 1 + 1 = 12 --> 16
          7 + 3 + 1 + 1 = 12 --> 21
          7 + 2 + 2 + 1 = 12 --> 28
          6 + 4 + 1 + 1 = 12 --> 24
          6 + 3 + 2 + 1 = 12 --> 36
          6 + 2 + 2 + 2 = 12 --> 48
          5 + 5 + 1 + 1 = 12 --> 25
          5 + 4 + 2 + 1 = 12 --> 40
          5 + 3 + 3 + 1 = 12 --> 45
          5 + 3 + 2 + 2 = 12 --> 60
          4 + 4 + 3 + 1 = 12 --> 48
          4 + 4 + 2 + 2 = 12 --> 64
          4 + 3 + 3 + 2 = 12 --> 72
          3 + 3 + 3 + 3 = 12 --> 81

          Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.







          share|improve this answer











          $endgroup$








          • 3




            $begingroup$
            Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
            $endgroup$
            – Kevin
            Mar 14 at 16:57













          15












          15








          15





          $begingroup$

          The mathematician owes




          48 dollars




          and the other faculty members owe




          4, 4, 3 and 1 dollar.




          Explanation:




          We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




          Table:




          9 + 1 + 1 + 1 = 12 --> 9
          8 + 2 + 1 + 1 = 12 --> 16
          7 + 3 + 1 + 1 = 12 --> 21
          7 + 2 + 2 + 1 = 12 --> 28
          6 + 4 + 1 + 1 = 12 --> 24
          6 + 3 + 2 + 1 = 12 --> 36
          6 + 2 + 2 + 2 = 12 --> 48
          5 + 5 + 1 + 1 = 12 --> 25
          5 + 4 + 2 + 1 = 12 --> 40
          5 + 3 + 3 + 1 = 12 --> 45
          5 + 3 + 2 + 2 = 12 --> 60
          4 + 4 + 3 + 1 = 12 --> 48
          4 + 4 + 2 + 2 = 12 --> 64
          4 + 3 + 3 + 2 = 12 --> 72
          3 + 3 + 3 + 3 = 12 --> 81

          Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.







          share|improve this answer











          $endgroup$



          The mathematician owes




          48 dollars




          and the other faculty members owe




          4, 4, 3 and 1 dollar.




          Explanation:




          We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




          Table:




          9 + 1 + 1 + 1 = 12 --> 9
          8 + 2 + 1 + 1 = 12 --> 16
          7 + 3 + 1 + 1 = 12 --> 21
          7 + 2 + 2 + 1 = 12 --> 28
          6 + 4 + 1 + 1 = 12 --> 24
          6 + 3 + 2 + 1 = 12 --> 36
          6 + 2 + 2 + 2 = 12 --> 48
          5 + 5 + 1 + 1 = 12 --> 25
          5 + 4 + 2 + 1 = 12 --> 40
          5 + 3 + 3 + 1 = 12 --> 45
          5 + 3 + 2 + 2 = 12 --> 60
          4 + 4 + 3 + 1 = 12 --> 48
          4 + 4 + 2 + 2 = 12 --> 64
          4 + 3 + 3 + 2 = 12 --> 72
          3 + 3 + 3 + 3 = 12 --> 81

          Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 14 at 19:31









          Yakk

          1706




          1706










          answered Mar 14 at 15:45









          GlorfindelGlorfindel

          14.1k45185




          14.1k45185







          • 3




            $begingroup$
            Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
            $endgroup$
            – Kevin
            Mar 14 at 16:57












          • 3




            $begingroup$
            Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
            $endgroup$
            – Kevin
            Mar 14 at 16:57







          3




          3




          $begingroup$
          Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
          $endgroup$
          – Kevin
          Mar 14 at 16:57




          $begingroup$
          Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
          $endgroup$
          – Kevin
          Mar 14 at 16:57











          5












          $begingroup$

          The mathematician owes




          $48




          Because




          nothing is said that the individual debts are unique, only that the lowest one must be.

          So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


          1,2,2,7 → $28

          1,2,3,6 → $36

          1,2,4,5 → $40

          1,3,3,5 → $45

          1,3,4,4 → $48




          Now the mathematician says at first that




          the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


          The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

          The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

          The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

          The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.







          share|improve this answer









          $endgroup$








          • 1




            $begingroup$
            In the second part, I think you are missing the possibility 2,3,3,4
            $endgroup$
            – Cain
            Mar 14 at 21:56















          5












          $begingroup$

          The mathematician owes




          $48




          Because




          nothing is said that the individual debts are unique, only that the lowest one must be.

          So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


          1,2,2,7 → $28

          1,2,3,6 → $36

          1,2,4,5 → $40

          1,3,3,5 → $45

          1,3,4,4 → $48




          Now the mathematician says at first that




          the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


          The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

          The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

          The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

          The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.







          share|improve this answer









          $endgroup$








          • 1




            $begingroup$
            In the second part, I think you are missing the possibility 2,3,3,4
            $endgroup$
            – Cain
            Mar 14 at 21:56













          5












          5








          5





          $begingroup$

          The mathematician owes




          $48




          Because




          nothing is said that the individual debts are unique, only that the lowest one must be.

          So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


          1,2,2,7 → $28

          1,2,3,6 → $36

          1,2,4,5 → $40

          1,3,3,5 → $45

          1,3,4,4 → $48




          Now the mathematician says at first that




          the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


          The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

          The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

          The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

          The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.







          share|improve this answer









          $endgroup$



          The mathematician owes




          $48




          Because




          nothing is said that the individual debts are unique, only that the lowest one must be.

          So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


          1,2,2,7 → $28

          1,2,3,6 → $36

          1,2,4,5 → $40

          1,3,3,5 → $45

          1,3,4,4 → $48




          Now the mathematician says at first that




          the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


          The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

          The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

          The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

          The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 14 at 15:59









          RubioRubio

          30.4k567188




          30.4k567188







          • 1




            $begingroup$
            In the second part, I think you are missing the possibility 2,3,3,4
            $endgroup$
            – Cain
            Mar 14 at 21:56












          • 1




            $begingroup$
            In the second part, I think you are missing the possibility 2,3,3,4
            $endgroup$
            – Cain
            Mar 14 at 21:56







          1




          1




          $begingroup$
          In the second part, I think you are missing the possibility 2,3,3,4
          $endgroup$
          – Cain
          Mar 14 at 21:56




          $begingroup$
          In the second part, I think you are missing the possibility 2,3,3,4
          $endgroup$
          – Cain
          Mar 14 at 21:56

















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          Kathakali Contents Etymology and nomenclature History Repertoire Songs and musical instruments Traditional plays Styles: Sampradayam Training centers and awards Relationship to other dance forms See also Notes References External links Navigation menueThe Illustrated Encyclopedia of Hinduism: A-MSouth Asian Folklore: An EncyclopediaRoutledge International Encyclopedia of Women: Global Women's Issues and KnowledgeKathakali Dance-drama: Where Gods and Demons Come to PlayKathakali Dance-drama: Where Gods and Demons Come to PlayKathakali Dance-drama: Where Gods and Demons Come to Play10.1353/atj.2005.0004The Illustrated Encyclopedia of Hinduism: A-MEncyclopedia of HinduismKathakali Dance-drama: Where Gods and Demons Come to PlaySonic Liturgy: Ritual and Music in Hindu Tradition"The Mirror of Gesture"Kathakali Dance-drama: Where Gods and Demons Come to Play"Kathakali"Indian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceMedieval Indian Literature: An AnthologyThe Oxford Companion to Indian TheatreSouth Asian Folklore: An Encyclopedia : Afghanistan, Bangladesh, India, Nepal, Pakistan, Sri LankaThe Rise of Performance Studies: Rethinking Richard Schechner's Broad SpectrumIndian Theatre: Traditions of PerformanceModern Asian Theatre and Performance 1900-2000Critical Theory and PerformanceBetween Theater and AnthropologyKathakali603847011Indian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceBetween Theater and AnthropologyBetween Theater and AnthropologyNambeesan Smaraka AwardsArchivedThe Cambridge Guide to TheatreRoutledge International Encyclopedia of Women: Global Women's Issues and KnowledgeThe Garland Encyclopedia of World Music: South Asia : the Indian subcontinentThe Ethos of Noh: Actors and Their Art10.2307/1145740By Means of Performance: Intercultural Studies of Theatre and Ritual10.1017/s204912550000100xReconceiving the Renaissance: A Critical ReaderPerformance TheoryListening to Theatre: The Aural Dimension of Beijing Opera10.2307/1146013Kathakali: The Art of the Non-WorldlyOn KathakaliKathakali, the dance theatreThe Kathakali Complex: Performance & StructureKathakali Dance-Drama: Where Gods and Demons Come to Play10.1093/obo/9780195399318-0071Drama and Ritual of Early Hinduism"In the Shadow of Hollywood Orientalism: Authentic East Indian Dancing"10.1080/08949460490274013Sanskrit Play Production in Ancient IndiaIndian Music: History and StructureBharata, the Nāṭyaśāstra233639306Table of Contents2238067286469807Dance In Indian Painting10.2307/32047833204783Kathakali Dance-Theatre: A Visual Narrative of Sacred Indian MimeIndian Classical Dance: The Renaissance and BeyondKathakali: an indigenous art-form of Keralaeee