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Algebra operations as natural transformations



The Next CEO of Stack OverflowMorphisms in the category of natural transformations?Understanding associators as natural transformationsWhat's the name of a morphism the morphism category of the category of categories?Natural transformations and the definition of Monoidal lax functorsWhat are the group objects in the category of finite sets and bijections, and its functor category?“Alternatives” to Natural TransformationsRepresenting natural transformations with diagramsBasic category theory: applying natural transformationsDefinition of category and natural transformationsCan natural transformations be viewed as functors between images of functors?










5












$begingroup$


Apologies in advance if the following makes little to no sense, but here goes ..



Denote $m_G : Gtimes Gto G$ the multiplication of a group $G$. Does it make sense to think of the map $m_G$ as some kind of morphism in a (at the moment unspecified) category?



Even more, could we think of the family $m_G$ (indexed by the class of groups) as a natural transformation of some or other functors?



Let's call our mystery categories $mathcal A$ and $mathcal B$ with mystery functors $X,Y :mathcal Atomathcal B$ such that the natural transformation condition holds:
$$ m_HX(f) = Y(f)m_G $$
where $f$ is a morphism in $mathcal A$ and $G,H$ are groups.



For this to make sense, we need a category with objects $Gtimes G$ and $G$. So, we extend (?) the category of groups by $mathcal B_0 := mboxGrp_0 cup Gtimes G mid GinmboxGrp_0$. Morphisms in 'separate components' remain as they are in $mboxGrp$ and $mboxGrptimesmboxGrp$ respectively. There would be no morphisms of the form $Gto Htimes H$ and
$$mathcal B(Gtimes G,H) := varphi m_G mid varphi in mboxHom(G,H) $$
where for every $x,yin G$ $varphi m_G (x,y) := varphi (xy) = varphi (x)varphi (y) =: m_H(varphi,varphi)(x,y)$. The identities are $1_G$ or $(1_G,1_G)$ depending on the component and composition of the morphisms would happen naturally.



  1. Is it guaranteed $(A,B) neq (A',B') implies mathcal B(A,B)capmathcal B(A',B') =emptyset, A,A',B,B'inmathcal B_0$?

  2. Taking $mathcal A = mboxGrp$ with $X :mathcal Atomathcal B$ given such that $X(G) = Gtimes G$ and for every morphism $f:Gto H$, $X(f) = (f,f)$. Put $Y:mathcal Atomathcal B$ as the embedding, then we would have $m_G$ as a natural transformation $XRightarrow Y$.

I omit the routine checks here, for they aren't important for this discussion. I am interested in whether this idea of regarding families of operations as natural transformations is, call it, well-founded



Questionnaire.



  1. Would such an approach be the only one? How else (if at all) would we regard the family $m_G$ as a natural transformation?

  2. Is this a more general thing in universal algebra? Given a class of algebras with certain operations of various arities, could we regard every family of operations as a natural transformation? (For instance, inverse operation or unit element operation of groups)









share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    @H.H. the components must also be morphisms themselves in the destination category so if it were to work, then that must involve some 'weird' categories. I'm concerned about the way I defined $mathcal B$ yet I can't find any rule that says a category can't contain objects of different 'type'.
    $endgroup$
    – Alvin Lepik
    Mar 18 at 11:27















5












$begingroup$


Apologies in advance if the following makes little to no sense, but here goes ..



Denote $m_G : Gtimes Gto G$ the multiplication of a group $G$. Does it make sense to think of the map $m_G$ as some kind of morphism in a (at the moment unspecified) category?



Even more, could we think of the family $m_G$ (indexed by the class of groups) as a natural transformation of some or other functors?



Let's call our mystery categories $mathcal A$ and $mathcal B$ with mystery functors $X,Y :mathcal Atomathcal B$ such that the natural transformation condition holds:
$$ m_HX(f) = Y(f)m_G $$
where $f$ is a morphism in $mathcal A$ and $G,H$ are groups.



For this to make sense, we need a category with objects $Gtimes G$ and $G$. So, we extend (?) the category of groups by $mathcal B_0 := mboxGrp_0 cup Gtimes G mid GinmboxGrp_0$. Morphisms in 'separate components' remain as they are in $mboxGrp$ and $mboxGrptimesmboxGrp$ respectively. There would be no morphisms of the form $Gto Htimes H$ and
$$mathcal B(Gtimes G,H) := varphi m_G mid varphi in mboxHom(G,H) $$
where for every $x,yin G$ $varphi m_G (x,y) := varphi (xy) = varphi (x)varphi (y) =: m_H(varphi,varphi)(x,y)$. The identities are $1_G$ or $(1_G,1_G)$ depending on the component and composition of the morphisms would happen naturally.



  1. Is it guaranteed $(A,B) neq (A',B') implies mathcal B(A,B)capmathcal B(A',B') =emptyset, A,A',B,B'inmathcal B_0$?

  2. Taking $mathcal A = mboxGrp$ with $X :mathcal Atomathcal B$ given such that $X(G) = Gtimes G$ and for every morphism $f:Gto H$, $X(f) = (f,f)$. Put $Y:mathcal Atomathcal B$ as the embedding, then we would have $m_G$ as a natural transformation $XRightarrow Y$.

I omit the routine checks here, for they aren't important for this discussion. I am interested in whether this idea of regarding families of operations as natural transformations is, call it, well-founded



Questionnaire.



  1. Would such an approach be the only one? How else (if at all) would we regard the family $m_G$ as a natural transformation?

  2. Is this a more general thing in universal algebra? Given a class of algebras with certain operations of various arities, could we regard every family of operations as a natural transformation? (For instance, inverse operation or unit element operation of groups)









share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    @H.H. the components must also be morphisms themselves in the destination category so if it were to work, then that must involve some 'weird' categories. I'm concerned about the way I defined $mathcal B$ yet I can't find any rule that says a category can't contain objects of different 'type'.
    $endgroup$
    – Alvin Lepik
    Mar 18 at 11:27













5












5








5


2



$begingroup$


Apologies in advance if the following makes little to no sense, but here goes ..



Denote $m_G : Gtimes Gto G$ the multiplication of a group $G$. Does it make sense to think of the map $m_G$ as some kind of morphism in a (at the moment unspecified) category?



Even more, could we think of the family $m_G$ (indexed by the class of groups) as a natural transformation of some or other functors?



Let's call our mystery categories $mathcal A$ and $mathcal B$ with mystery functors $X,Y :mathcal Atomathcal B$ such that the natural transformation condition holds:
$$ m_HX(f) = Y(f)m_G $$
where $f$ is a morphism in $mathcal A$ and $G,H$ are groups.



For this to make sense, we need a category with objects $Gtimes G$ and $G$. So, we extend (?) the category of groups by $mathcal B_0 := mboxGrp_0 cup Gtimes G mid GinmboxGrp_0$. Morphisms in 'separate components' remain as they are in $mboxGrp$ and $mboxGrptimesmboxGrp$ respectively. There would be no morphisms of the form $Gto Htimes H$ and
$$mathcal B(Gtimes G,H) := varphi m_G mid varphi in mboxHom(G,H) $$
where for every $x,yin G$ $varphi m_G (x,y) := varphi (xy) = varphi (x)varphi (y) =: m_H(varphi,varphi)(x,y)$. The identities are $1_G$ or $(1_G,1_G)$ depending on the component and composition of the morphisms would happen naturally.



  1. Is it guaranteed $(A,B) neq (A',B') implies mathcal B(A,B)capmathcal B(A',B') =emptyset, A,A',B,B'inmathcal B_0$?

  2. Taking $mathcal A = mboxGrp$ with $X :mathcal Atomathcal B$ given such that $X(G) = Gtimes G$ and for every morphism $f:Gto H$, $X(f) = (f,f)$. Put $Y:mathcal Atomathcal B$ as the embedding, then we would have $m_G$ as a natural transformation $XRightarrow Y$.

I omit the routine checks here, for they aren't important for this discussion. I am interested in whether this idea of regarding families of operations as natural transformations is, call it, well-founded



Questionnaire.



  1. Would such an approach be the only one? How else (if at all) would we regard the family $m_G$ as a natural transformation?

  2. Is this a more general thing in universal algebra? Given a class of algebras with certain operations of various arities, could we regard every family of operations as a natural transformation? (For instance, inverse operation or unit element operation of groups)









share|cite|improve this question











$endgroup$




Apologies in advance if the following makes little to no sense, but here goes ..



Denote $m_G : Gtimes Gto G$ the multiplication of a group $G$. Does it make sense to think of the map $m_G$ as some kind of morphism in a (at the moment unspecified) category?



Even more, could we think of the family $m_G$ (indexed by the class of groups) as a natural transformation of some or other functors?



Let's call our mystery categories $mathcal A$ and $mathcal B$ with mystery functors $X,Y :mathcal Atomathcal B$ such that the natural transformation condition holds:
$$ m_HX(f) = Y(f)m_G $$
where $f$ is a morphism in $mathcal A$ and $G,H$ are groups.



For this to make sense, we need a category with objects $Gtimes G$ and $G$. So, we extend (?) the category of groups by $mathcal B_0 := mboxGrp_0 cup Gtimes G mid GinmboxGrp_0$. Morphisms in 'separate components' remain as they are in $mboxGrp$ and $mboxGrptimesmboxGrp$ respectively. There would be no morphisms of the form $Gto Htimes H$ and
$$mathcal B(Gtimes G,H) := varphi m_G mid varphi in mboxHom(G,H) $$
where for every $x,yin G$ $varphi m_G (x,y) := varphi (xy) = varphi (x)varphi (y) =: m_H(varphi,varphi)(x,y)$. The identities are $1_G$ or $(1_G,1_G)$ depending on the component and composition of the morphisms would happen naturally.



  1. Is it guaranteed $(A,B) neq (A',B') implies mathcal B(A,B)capmathcal B(A',B') =emptyset, A,A',B,B'inmathcal B_0$?

  2. Taking $mathcal A = mboxGrp$ with $X :mathcal Atomathcal B$ given such that $X(G) = Gtimes G$ and for every morphism $f:Gto H$, $X(f) = (f,f)$. Put $Y:mathcal Atomathcal B$ as the embedding, then we would have $m_G$ as a natural transformation $XRightarrow Y$.

I omit the routine checks here, for they aren't important for this discussion. I am interested in whether this idea of regarding families of operations as natural transformations is, call it, well-founded



Questionnaire.



  1. Would such an approach be the only one? How else (if at all) would we regard the family $m_G$ as a natural transformation?

  2. Is this a more general thing in universal algebra? Given a class of algebras with certain operations of various arities, could we regard every family of operations as a natural transformation? (For instance, inverse operation or unit element operation of groups)






group-theory category-theory universal-algebra natural-transformations






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 18 at 11:13







Alvin Lepik

















asked Mar 18 at 10:54









Alvin LepikAlvin Lepik

2,7961924




2,7961924







  • 1




    $begingroup$
    @H.H. the components must also be morphisms themselves in the destination category so if it were to work, then that must involve some 'weird' categories. I'm concerned about the way I defined $mathcal B$ yet I can't find any rule that says a category can't contain objects of different 'type'.
    $endgroup$
    – Alvin Lepik
    Mar 18 at 11:27












  • 1




    $begingroup$
    @H.H. the components must also be morphisms themselves in the destination category so if it were to work, then that must involve some 'weird' categories. I'm concerned about the way I defined $mathcal B$ yet I can't find any rule that says a category can't contain objects of different 'type'.
    $endgroup$
    – Alvin Lepik
    Mar 18 at 11:27







1




1




$begingroup$
@H.H. the components must also be morphisms themselves in the destination category so if it were to work, then that must involve some 'weird' categories. I'm concerned about the way I defined $mathcal B$ yet I can't find any rule that says a category can't contain objects of different 'type'.
$endgroup$
– Alvin Lepik
Mar 18 at 11:27




$begingroup$
@H.H. the components must also be morphisms themselves in the destination category so if it were to work, then that must involve some 'weird' categories. I'm concerned about the way I defined $mathcal B$ yet I can't find any rule that says a category can't contain objects of different 'type'.
$endgroup$
– Alvin Lepik
Mar 18 at 11:27










1 Answer
1






active

oldest

votes


















4












$begingroup$

Let $DeclareMathOperatorSetSetSet$ denote the category of sets and $DeclareMathOperatorGrpGrpGrp$ denote the category of groups.
Let $Upsilon:GrptoSet$ denote the forgetful functor and $Delta:SettoSet$ be the diagonal functor $Delta(X)=Xtimes X$.



Then you are looking for a natural transformation $mu:DeltacircUpsilontoUpsilon$.
If $X$ is a group, then $Upsilon(X)$ is its underlying set.
For each group $X$ let $mu_X:(DeltacircUpsilon)(X)toUpsilon(X)$ be its composition law.
If $f:Xto Y$ is a group homomorphism, then we have a commutative diagram$requireAMScd$:
beginCD
Upsilon(X)timesUpsilon(X)@=(DeltacircUpsilon)(X)@>mu_X>>Upsilon(X)\
@VUpsilon(f)timesUpsilon(f)VV@V(DeltacircUpsilon)(f)VV@VVUpsilon(f)V\
Upsilon(Y)timesUpsilon(Y)@=(DeltacircUpsilon)(Y)@>>mu_Y >Upsilon(Y)
endCD

which proves naturalness of $mu_X$.






share|cite|improve this answer











$endgroup$








  • 1




    $begingroup$
    This looks much neater and cleaner than my attempt. Thanks, I have a much better understanding of this idea now.
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:31










  • $begingroup$
    Also thanks for demonstrating the amscd package, looks much more convenient than tikz syntax-wise. Can't believe I didn't know about it!
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:44











Your Answer





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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4












$begingroup$

Let $DeclareMathOperatorSetSetSet$ denote the category of sets and $DeclareMathOperatorGrpGrpGrp$ denote the category of groups.
Let $Upsilon:GrptoSet$ denote the forgetful functor and $Delta:SettoSet$ be the diagonal functor $Delta(X)=Xtimes X$.



Then you are looking for a natural transformation $mu:DeltacircUpsilontoUpsilon$.
If $X$ is a group, then $Upsilon(X)$ is its underlying set.
For each group $X$ let $mu_X:(DeltacircUpsilon)(X)toUpsilon(X)$ be its composition law.
If $f:Xto Y$ is a group homomorphism, then we have a commutative diagram$requireAMScd$:
beginCD
Upsilon(X)timesUpsilon(X)@=(DeltacircUpsilon)(X)@>mu_X>>Upsilon(X)\
@VUpsilon(f)timesUpsilon(f)VV@V(DeltacircUpsilon)(f)VV@VVUpsilon(f)V\
Upsilon(Y)timesUpsilon(Y)@=(DeltacircUpsilon)(Y)@>>mu_Y >Upsilon(Y)
endCD

which proves naturalness of $mu_X$.






share|cite|improve this answer











$endgroup$








  • 1




    $begingroup$
    This looks much neater and cleaner than my attempt. Thanks, I have a much better understanding of this idea now.
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:31










  • $begingroup$
    Also thanks for demonstrating the amscd package, looks much more convenient than tikz syntax-wise. Can't believe I didn't know about it!
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:44















4












$begingroup$

Let $DeclareMathOperatorSetSetSet$ denote the category of sets and $DeclareMathOperatorGrpGrpGrp$ denote the category of groups.
Let $Upsilon:GrptoSet$ denote the forgetful functor and $Delta:SettoSet$ be the diagonal functor $Delta(X)=Xtimes X$.



Then you are looking for a natural transformation $mu:DeltacircUpsilontoUpsilon$.
If $X$ is a group, then $Upsilon(X)$ is its underlying set.
For each group $X$ let $mu_X:(DeltacircUpsilon)(X)toUpsilon(X)$ be its composition law.
If $f:Xto Y$ is a group homomorphism, then we have a commutative diagram$requireAMScd$:
beginCD
Upsilon(X)timesUpsilon(X)@=(DeltacircUpsilon)(X)@>mu_X>>Upsilon(X)\
@VUpsilon(f)timesUpsilon(f)VV@V(DeltacircUpsilon)(f)VV@VVUpsilon(f)V\
Upsilon(Y)timesUpsilon(Y)@=(DeltacircUpsilon)(Y)@>>mu_Y >Upsilon(Y)
endCD

which proves naturalness of $mu_X$.






share|cite|improve this answer











$endgroup$








  • 1




    $begingroup$
    This looks much neater and cleaner than my attempt. Thanks, I have a much better understanding of this idea now.
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:31










  • $begingroup$
    Also thanks for demonstrating the amscd package, looks much more convenient than tikz syntax-wise. Can't believe I didn't know about it!
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:44













4












4








4





$begingroup$

Let $DeclareMathOperatorSetSetSet$ denote the category of sets and $DeclareMathOperatorGrpGrpGrp$ denote the category of groups.
Let $Upsilon:GrptoSet$ denote the forgetful functor and $Delta:SettoSet$ be the diagonal functor $Delta(X)=Xtimes X$.



Then you are looking for a natural transformation $mu:DeltacircUpsilontoUpsilon$.
If $X$ is a group, then $Upsilon(X)$ is its underlying set.
For each group $X$ let $mu_X:(DeltacircUpsilon)(X)toUpsilon(X)$ be its composition law.
If $f:Xto Y$ is a group homomorphism, then we have a commutative diagram$requireAMScd$:
beginCD
Upsilon(X)timesUpsilon(X)@=(DeltacircUpsilon)(X)@>mu_X>>Upsilon(X)\
@VUpsilon(f)timesUpsilon(f)VV@V(DeltacircUpsilon)(f)VV@VVUpsilon(f)V\
Upsilon(Y)timesUpsilon(Y)@=(DeltacircUpsilon)(Y)@>>mu_Y >Upsilon(Y)
endCD

which proves naturalness of $mu_X$.






share|cite|improve this answer











$endgroup$



Let $DeclareMathOperatorSetSetSet$ denote the category of sets and $DeclareMathOperatorGrpGrpGrp$ denote the category of groups.
Let $Upsilon:GrptoSet$ denote the forgetful functor and $Delta:SettoSet$ be the diagonal functor $Delta(X)=Xtimes X$.



Then you are looking for a natural transformation $mu:DeltacircUpsilontoUpsilon$.
If $X$ is a group, then $Upsilon(X)$ is its underlying set.
For each group $X$ let $mu_X:(DeltacircUpsilon)(X)toUpsilon(X)$ be its composition law.
If $f:Xto Y$ is a group homomorphism, then we have a commutative diagram$requireAMScd$:
beginCD
Upsilon(X)timesUpsilon(X)@=(DeltacircUpsilon)(X)@>mu_X>>Upsilon(X)\
@VUpsilon(f)timesUpsilon(f)VV@V(DeltacircUpsilon)(f)VV@VVUpsilon(f)V\
Upsilon(Y)timesUpsilon(Y)@=(DeltacircUpsilon)(Y)@>>mu_Y >Upsilon(Y)
endCD

which proves naturalness of $mu_X$.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Mar 19 at 16:23









Litho

3,4671716




3,4671716










answered Mar 18 at 12:18









Fabio LucchiniFabio Lucchini

9,56611426




9,56611426







  • 1




    $begingroup$
    This looks much neater and cleaner than my attempt. Thanks, I have a much better understanding of this idea now.
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:31










  • $begingroup$
    Also thanks for demonstrating the amscd package, looks much more convenient than tikz syntax-wise. Can't believe I didn't know about it!
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:44












  • 1




    $begingroup$
    This looks much neater and cleaner than my attempt. Thanks, I have a much better understanding of this idea now.
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:31










  • $begingroup$
    Also thanks for demonstrating the amscd package, looks much more convenient than tikz syntax-wise. Can't believe I didn't know about it!
    $endgroup$
    – Alvin Lepik
    Mar 18 at 12:44







1




1




$begingroup$
This looks much neater and cleaner than my attempt. Thanks, I have a much better understanding of this idea now.
$endgroup$
– Alvin Lepik
Mar 18 at 12:31




$begingroup$
This looks much neater and cleaner than my attempt. Thanks, I have a much better understanding of this idea now.
$endgroup$
– Alvin Lepik
Mar 18 at 12:31












$begingroup$
Also thanks for demonstrating the amscd package, looks much more convenient than tikz syntax-wise. Can't believe I didn't know about it!
$endgroup$
– Alvin Lepik
Mar 18 at 12:44




$begingroup$
Also thanks for demonstrating the amscd package, looks much more convenient than tikz syntax-wise. Can't believe I didn't know about it!
$endgroup$
– Alvin Lepik
Mar 18 at 12:44

















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Kathakali Contents Etymology and nomenclature History Repertoire Songs and musical instruments Traditional plays Styles: Sampradayam Training centers and awards Relationship to other dance forms See also Notes References External links Navigation menueThe Illustrated Encyclopedia of Hinduism: A-MSouth Asian Folklore: An EncyclopediaRoutledge International Encyclopedia of Women: Global Women's Issues and KnowledgeKathakali Dance-drama: Where Gods and Demons Come to PlayKathakali Dance-drama: Where Gods and Demons Come to PlayKathakali Dance-drama: Where Gods and Demons Come to Play10.1353/atj.2005.0004The Illustrated Encyclopedia of Hinduism: A-MEncyclopedia of HinduismKathakali Dance-drama: Where Gods and Demons Come to PlaySonic Liturgy: Ritual and Music in Hindu Tradition"The Mirror of Gesture"Kathakali Dance-drama: Where Gods and Demons Come to Play"Kathakali"Indian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceMedieval Indian Literature: An AnthologyThe Oxford Companion to Indian TheatreSouth Asian Folklore: An Encyclopedia : Afghanistan, Bangladesh, India, Nepal, Pakistan, Sri LankaThe Rise of Performance Studies: Rethinking Richard Schechner's Broad SpectrumIndian Theatre: Traditions of PerformanceModern Asian Theatre and Performance 1900-2000Critical Theory and PerformanceBetween Theater and AnthropologyKathakali603847011Indian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceBetween Theater and AnthropologyBetween Theater and AnthropologyNambeesan Smaraka AwardsArchivedThe Cambridge Guide to TheatreRoutledge International Encyclopedia of Women: Global Women's Issues and KnowledgeThe Garland Encyclopedia of World Music: South Asia : the Indian subcontinentThe Ethos of Noh: Actors and Their Art10.2307/1145740By Means of Performance: Intercultural Studies of Theatre and Ritual10.1017/s204912550000100xReconceiving the Renaissance: A Critical ReaderPerformance TheoryListening to Theatre: The Aural Dimension of Beijing Opera10.2307/1146013Kathakali: The Art of the Non-WorldlyOn KathakaliKathakali, the dance theatreThe Kathakali Complex: Performance & StructureKathakali Dance-Drama: Where Gods and Demons Come to Play10.1093/obo/9780195399318-0071Drama and Ritual of Early Hinduism"In the Shadow of Hollywood Orientalism: Authentic East Indian Dancing"10.1080/08949460490274013Sanskrit Play Production in Ancient IndiaIndian Music: History and StructureBharata, the Nāṭyaśāstra233639306Table of Contents2238067286469807Dance In Indian Painting10.2307/32047833204783Kathakali Dance-Theatre: A Visual Narrative of Sacred Indian MimeIndian Classical Dance: The Renaissance and BeyondKathakali: an indigenous art-form of Keralaeee

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