Solution by set Algebra Instead of Venn diagram for following questionFuzzy Venn diagram regions labeled in ternaryA problem on Venn diagramThree set Venn diagram$A Delta C = B Delta C$, then prove that $A = B$ where $Delta$ is a symmetric difference operation.Simple sample space probability questionIs the set ∅ part of the set UBoolean Algebra Union and Intersectionis this venn diagram of posets, osets and lattices correct?True or False: $A ∩ B = ∅ $ and $B ∩ C = ∅$, then $A ∩ C = ∅$?Venn Diagram tool to help with learning set theory
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Solution by set Algebra Instead of Venn diagram for following question
Fuzzy Venn diagram regions labeled in ternaryA problem on Venn diagramThree set Venn diagram$A Delta C = B Delta C$, then prove that $A = B$ where $Delta$ is a symmetric difference operation.Simple sample space probability questionIs the set ∅ part of the set UBoolean Algebra Union and Intersectionis this venn diagram of posets, osets and lattices correct?True or False: $A ∩ B = ∅ $ and $B ∩ C = ∅$, then $A ∩ C = ∅$?Venn Diagram tool to help with learning set theory
$begingroup$
(P ∩ Q ∩ R) U (P′∩ Q ∩ R)U Q′U R′
I am able to solve the set algebraic equation through Venn diagram and the solution is as under:

set 1 = $(P ∩ Q ∩ R)$ is region 1
set 2 = $(P′∩ Q ∩ R)$ is region 2
set 3 = $Q'$ belongs to regions 4+3+6+8
set 4 = $R'$ belongs to regions 4+7+5+8
and the union of set 1 1 set 2 2 set 3 4,3,6,8 set 4 4,7,5,8
will be 1,2,3,4,5,6,7,8 that is the universal set itself. I am able to get the correct answer but my approach is through Venn diagram. But some where I have found some algebraic approach through some set operation that I am not able to understand. Can somebody please guide me?
Following is the link of the algebraic approach.
Please click here
elementary-set-theory
$endgroup$
add a comment |
$begingroup$
(P ∩ Q ∩ R) U (P′∩ Q ∩ R)U Q′U R′
I am able to solve the set algebraic equation through Venn diagram and the solution is as under:

set 1 = $(P ∩ Q ∩ R)$ is region 1
set 2 = $(P′∩ Q ∩ R)$ is region 2
set 3 = $Q'$ belongs to regions 4+3+6+8
set 4 = $R'$ belongs to regions 4+7+5+8
and the union of set 1 1 set 2 2 set 3 4,3,6,8 set 4 4,7,5,8
will be 1,2,3,4,5,6,7,8 that is the universal set itself. I am able to get the correct answer but my approach is through Venn diagram. But some where I have found some algebraic approach through some set operation that I am not able to understand. Can somebody please guide me?
Following is the link of the algebraic approach.
Please click here
elementary-set-theory
$endgroup$
1
$begingroup$
You can start applying Distributivity to $(P cap Q cap R) cup (P′ cap Q cap R)$ to get $(Q cap R)$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:55
$begingroup$
Then apply De Morgan to $(Q′ cup R′)$ to get $(Q cap R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Now you have : $(Q∩R) cup (Q∩R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Got it . Thank you @Mauro ALLEGRANZA
$endgroup$
– Thinker
2 days ago
add a comment |
$begingroup$
(P ∩ Q ∩ R) U (P′∩ Q ∩ R)U Q′U R′
I am able to solve the set algebraic equation through Venn diagram and the solution is as under:

set 1 = $(P ∩ Q ∩ R)$ is region 1
set 2 = $(P′∩ Q ∩ R)$ is region 2
set 3 = $Q'$ belongs to regions 4+3+6+8
set 4 = $R'$ belongs to regions 4+7+5+8
and the union of set 1 1 set 2 2 set 3 4,3,6,8 set 4 4,7,5,8
will be 1,2,3,4,5,6,7,8 that is the universal set itself. I am able to get the correct answer but my approach is through Venn diagram. But some where I have found some algebraic approach through some set operation that I am not able to understand. Can somebody please guide me?
Following is the link of the algebraic approach.
Please click here
elementary-set-theory
$endgroup$
(P ∩ Q ∩ R) U (P′∩ Q ∩ R)U Q′U R′
I am able to solve the set algebraic equation through Venn diagram and the solution is as under:

set 1 = $(P ∩ Q ∩ R)$ is region 1
set 2 = $(P′∩ Q ∩ R)$ is region 2
set 3 = $Q'$ belongs to regions 4+3+6+8
set 4 = $R'$ belongs to regions 4+7+5+8
and the union of set 1 1 set 2 2 set 3 4,3,6,8 set 4 4,7,5,8
will be 1,2,3,4,5,6,7,8 that is the universal set itself. I am able to get the correct answer but my approach is through Venn diagram. But some where I have found some algebraic approach through some set operation that I am not able to understand. Can somebody please guide me?
Following is the link of the algebraic approach.
Please click here
elementary-set-theory
elementary-set-theory
edited Mar 12 at 8:48
Mauro ALLEGRANZA
67.1k449115
67.1k449115
asked Mar 12 at 8:22
ThinkerThinker
63
63
1
$begingroup$
You can start applying Distributivity to $(P cap Q cap R) cup (P′ cap Q cap R)$ to get $(Q cap R)$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:55
$begingroup$
Then apply De Morgan to $(Q′ cup R′)$ to get $(Q cap R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Now you have : $(Q∩R) cup (Q∩R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Got it . Thank you @Mauro ALLEGRANZA
$endgroup$
– Thinker
2 days ago
add a comment |
1
$begingroup$
You can start applying Distributivity to $(P cap Q cap R) cup (P′ cap Q cap R)$ to get $(Q cap R)$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:55
$begingroup$
Then apply De Morgan to $(Q′ cup R′)$ to get $(Q cap R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Now you have : $(Q∩R) cup (Q∩R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Got it . Thank you @Mauro ALLEGRANZA
$endgroup$
– Thinker
2 days ago
1
1
$begingroup$
You can start applying Distributivity to $(P cap Q cap R) cup (P′ cap Q cap R)$ to get $(Q cap R)$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:55
$begingroup$
You can start applying Distributivity to $(P cap Q cap R) cup (P′ cap Q cap R)$ to get $(Q cap R)$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:55
$begingroup$
Then apply De Morgan to $(Q′ cup R′)$ to get $(Q cap R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Then apply De Morgan to $(Q′ cup R′)$ to get $(Q cap R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Now you have : $(Q∩R) cup (Q∩R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Now you have : $(Q∩R) cup (Q∩R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Got it . Thank you @Mauro ALLEGRANZA
$endgroup$
– Thinker
2 days ago
$begingroup$
Got it . Thank you @Mauro ALLEGRANZA
$endgroup$
– Thinker
2 days ago
add a comment |
0
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oldest
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1
$begingroup$
You can start applying Distributivity to $(P cap Q cap R) cup (P′ cap Q cap R)$ to get $(Q cap R)$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:55
$begingroup$
Then apply De Morgan to $(Q′ cup R′)$ to get $(Q cap R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Now you have : $(Q∩R) cup (Q∩R)'$.
$endgroup$
– Mauro ALLEGRANZA
Mar 12 at 8:57
$begingroup$
Got it . Thank you @Mauro ALLEGRANZA
$endgroup$
– Thinker
2 days ago