How to prove that this function is differentiable?How to know this function is continuous and differentiable?Prove that $f$ is differentiable at $(x)=0$ using formal definitionproving that a certain function is not differentiable at $(0,0)$Showing that this function is infinitely differentiableIs this function differentiable at the origin?How do I prove this function is differentiable at 0?Is this function differentiable in $(1,-1)$?Prove that a function is not continuously differentiableProve this function is differentiable at a point but the partial derivatives are not continuousProve function is not differentiable even though all directional derivatives exist and it is continuous.

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How to prove that this function is differentiable?


How to know this function is continuous and differentiable?Prove that $f$ is differentiable at $(x)=0$ using formal definitionproving that a certain function is not differentiable at $(0,0)$Showing that this function is infinitely differentiableIs this function differentiable at the origin?How do I prove this function is differentiable at 0?Is this function differentiable in $(1,-1)$?Prove that a function is not continuously differentiableProve this function is differentiable at a point but the partial derivatives are not continuousProve function is not differentiable even though all directional derivatives exist and it is continuous.













1












$begingroup$



Let $$f(x,y)=begincases(x^2+y^2) sinleft(frac1x^2+y^2right)&textif;x^2+y^2 neq 0\\0&textotherwise endcases$$



Prove that $f$ is differentiable




Could anyone give me a hint please?










share|cite|improve this question











$endgroup$
















    1












    $begingroup$



    Let $$f(x,y)=begincases(x^2+y^2) sinleft(frac1x^2+y^2right)&textif;x^2+y^2 neq 0\\0&textotherwise endcases$$



    Prove that $f$ is differentiable




    Could anyone give me a hint please?










    share|cite|improve this question











    $endgroup$














      1












      1








      1





      $begingroup$



      Let $$f(x,y)=begincases(x^2+y^2) sinleft(frac1x^2+y^2right)&textif;x^2+y^2 neq 0\\0&textotherwise endcases$$



      Prove that $f$ is differentiable




      Could anyone give me a hint please?










      share|cite|improve this question











      $endgroup$





      Let $$f(x,y)=begincases(x^2+y^2) sinleft(frac1x^2+y^2right)&textif;x^2+y^2 neq 0\\0&textotherwise endcases$$



      Prove that $f$ is differentiable




      Could anyone give me a hint please?







      calculus multivariable-calculus derivatives






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 12 at 10:48









      Chinnapparaj R

      5,7332928




      5,7332928










      asked Mar 12 at 10:43









      IntuitionIntuition

      1,108826




      1,108826




















          2 Answers
          2






          active

          oldest

          votes


















          1












          $begingroup$

          Hint: Prove that$$lim_(x,y)to(0,0)fracf(x,y)-f(0,0)lVert(x,y)rVert=0.$$






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            what about not (0,0)?
            $endgroup$
            – Intuition
            Mar 12 at 11:02










          • $begingroup$
            why we do this?
            $endgroup$
            – Intuition
            Mar 12 at 11:03










          • $begingroup$
            Outside $(0,0)$, your function can be expressed from differentiable functions using arithmetic operations and composition. Therefore, it is differentiable there.
            $endgroup$
            – José Carlos Santos
            Mar 12 at 11:04










          • $begingroup$
            We do this in order to prove that $f'(0,0)$ is the null function.
            $endgroup$
            – José Carlos Santos
            Mar 12 at 11:05










          • $begingroup$
            why we want to prove this?
            $endgroup$
            – Intuition
            Mar 12 at 11:07


















          1












          $begingroup$

          Hint: Use the polar coordinates
          $$x = r costheta \ y = r sin theta$$



          and simplify $f(x,y) to f(r, theta)$.






          share|cite|improve this answer









          $endgroup$












            Your Answer





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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1












            $begingroup$

            Hint: Prove that$$lim_(x,y)to(0,0)fracf(x,y)-f(0,0)lVert(x,y)rVert=0.$$






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              what about not (0,0)?
              $endgroup$
              – Intuition
              Mar 12 at 11:02










            • $begingroup$
              why we do this?
              $endgroup$
              – Intuition
              Mar 12 at 11:03










            • $begingroup$
              Outside $(0,0)$, your function can be expressed from differentiable functions using arithmetic operations and composition. Therefore, it is differentiable there.
              $endgroup$
              – José Carlos Santos
              Mar 12 at 11:04










            • $begingroup$
              We do this in order to prove that $f'(0,0)$ is the null function.
              $endgroup$
              – José Carlos Santos
              Mar 12 at 11:05










            • $begingroup$
              why we want to prove this?
              $endgroup$
              – Intuition
              Mar 12 at 11:07















            1












            $begingroup$

            Hint: Prove that$$lim_(x,y)to(0,0)fracf(x,y)-f(0,0)lVert(x,y)rVert=0.$$






            share|cite|improve this answer









            $endgroup$












            • $begingroup$
              what about not (0,0)?
              $endgroup$
              – Intuition
              Mar 12 at 11:02










            • $begingroup$
              why we do this?
              $endgroup$
              – Intuition
              Mar 12 at 11:03










            • $begingroup$
              Outside $(0,0)$, your function can be expressed from differentiable functions using arithmetic operations and composition. Therefore, it is differentiable there.
              $endgroup$
              – José Carlos Santos
              Mar 12 at 11:04










            • $begingroup$
              We do this in order to prove that $f'(0,0)$ is the null function.
              $endgroup$
              – José Carlos Santos
              Mar 12 at 11:05










            • $begingroup$
              why we want to prove this?
              $endgroup$
              – Intuition
              Mar 12 at 11:07













            1












            1








            1





            $begingroup$

            Hint: Prove that$$lim_(x,y)to(0,0)fracf(x,y)-f(0,0)lVert(x,y)rVert=0.$$






            share|cite|improve this answer









            $endgroup$



            Hint: Prove that$$lim_(x,y)to(0,0)fracf(x,y)-f(0,0)lVert(x,y)rVert=0.$$







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Mar 12 at 10:57









            José Carlos SantosJosé Carlos Santos

            168k22132236




            168k22132236











            • $begingroup$
              what about not (0,0)?
              $endgroup$
              – Intuition
              Mar 12 at 11:02










            • $begingroup$
              why we do this?
              $endgroup$
              – Intuition
              Mar 12 at 11:03










            • $begingroup$
              Outside $(0,0)$, your function can be expressed from differentiable functions using arithmetic operations and composition. Therefore, it is differentiable there.
              $endgroup$
              – José Carlos Santos
              Mar 12 at 11:04










            • $begingroup$
              We do this in order to prove that $f'(0,0)$ is the null function.
              $endgroup$
              – José Carlos Santos
              Mar 12 at 11:05










            • $begingroup$
              why we want to prove this?
              $endgroup$
              – Intuition
              Mar 12 at 11:07
















            • $begingroup$
              what about not (0,0)?
              $endgroup$
              – Intuition
              Mar 12 at 11:02










            • $begingroup$
              why we do this?
              $endgroup$
              – Intuition
              Mar 12 at 11:03










            • $begingroup$
              Outside $(0,0)$, your function can be expressed from differentiable functions using arithmetic operations and composition. Therefore, it is differentiable there.
              $endgroup$
              – José Carlos Santos
              Mar 12 at 11:04










            • $begingroup$
              We do this in order to prove that $f'(0,0)$ is the null function.
              $endgroup$
              – José Carlos Santos
              Mar 12 at 11:05










            • $begingroup$
              why we want to prove this?
              $endgroup$
              – Intuition
              Mar 12 at 11:07















            $begingroup$
            what about not (0,0)?
            $endgroup$
            – Intuition
            Mar 12 at 11:02




            $begingroup$
            what about not (0,0)?
            $endgroup$
            – Intuition
            Mar 12 at 11:02












            $begingroup$
            why we do this?
            $endgroup$
            – Intuition
            Mar 12 at 11:03




            $begingroup$
            why we do this?
            $endgroup$
            – Intuition
            Mar 12 at 11:03












            $begingroup$
            Outside $(0,0)$, your function can be expressed from differentiable functions using arithmetic operations and composition. Therefore, it is differentiable there.
            $endgroup$
            – José Carlos Santos
            Mar 12 at 11:04




            $begingroup$
            Outside $(0,0)$, your function can be expressed from differentiable functions using arithmetic operations and composition. Therefore, it is differentiable there.
            $endgroup$
            – José Carlos Santos
            Mar 12 at 11:04












            $begingroup$
            We do this in order to prove that $f'(0,0)$ is the null function.
            $endgroup$
            – José Carlos Santos
            Mar 12 at 11:05




            $begingroup$
            We do this in order to prove that $f'(0,0)$ is the null function.
            $endgroup$
            – José Carlos Santos
            Mar 12 at 11:05












            $begingroup$
            why we want to prove this?
            $endgroup$
            – Intuition
            Mar 12 at 11:07




            $begingroup$
            why we want to prove this?
            $endgroup$
            – Intuition
            Mar 12 at 11:07











            1












            $begingroup$

            Hint: Use the polar coordinates
            $$x = r costheta \ y = r sin theta$$



            and simplify $f(x,y) to f(r, theta)$.






            share|cite|improve this answer









            $endgroup$

















              1












              $begingroup$

              Hint: Use the polar coordinates
              $$x = r costheta \ y = r sin theta$$



              and simplify $f(x,y) to f(r, theta)$.






              share|cite|improve this answer









              $endgroup$















                1












                1








                1





                $begingroup$

                Hint: Use the polar coordinates
                $$x = r costheta \ y = r sin theta$$



                and simplify $f(x,y) to f(r, theta)$.






                share|cite|improve this answer









                $endgroup$



                Hint: Use the polar coordinates
                $$x = r costheta \ y = r sin theta$$



                and simplify $f(x,y) to f(r, theta)$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Mar 12 at 11:03









                Piotr BenedysiukPiotr Benedysiuk

                1,344519




                1,344519



























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