value of $a,b$ in trigonometric expressionRation of sum and Product of Trigonometric expression.Value of $sec^2 a+2sec^2 b$Finding value of $k$ in trigonometric equation.Finding smallest positive root $sqrtsin(1-x)=sqrtcos x$Trigonometric series sum involving tangentsFind all integers $m$ and $n$ such that $ncosfracpim= sqrt8+sqrt32+sqrt768$If $cos^4 alpha+4sin^4 beta-4sqrt2cos alpha sin beta +2=0$, then find $alpha$, $beta$ in $(0,fracpi2)$value of $x$ in Trigonometric equationTrigonometric series sum with $sin$ functionfinding wired trigononetric ratio

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value of $a,b$ in trigonometric expression


Ration of sum and Product of Trigonometric expression.Value of $sec^2 a+2sec^2 b$Finding value of $k$ in trigonometric equation.Finding smallest positive root $sqrtsin(1-x)=sqrtcos x$Trigonometric series sum involving tangentsFind all integers $m$ and $n$ such that $ncosfracpim= sqrt8+sqrt32+sqrt768$If $cos^4 alpha+4sin^4 beta-4sqrt2cos alpha sin beta +2=0$, then find $alpha$, $beta$ in $(0,fracpi2)$value of $x$ in Trigonometric equationTrigonometric series sum with $sin$ functionfinding wired trigononetric ratio













1












$begingroup$


If $a,b$ are positive integers such that $displaystyle sqrt8+sqrt32+sqrt768=acosbigg(fracpibbigg)$



what i try: i am trying to convert it into $displaystyle sqrt2+2cos 8x=sqrt2cos 4x$



How do i solve it Help me please










share|cite|improve this question









$endgroup$
















    1












    $begingroup$


    If $a,b$ are positive integers such that $displaystyle sqrt8+sqrt32+sqrt768=acosbigg(fracpibbigg)$



    what i try: i am trying to convert it into $displaystyle sqrt2+2cos 8x=sqrt2cos 4x$



    How do i solve it Help me please










    share|cite|improve this question









    $endgroup$














      1












      1








      1





      $begingroup$


      If $a,b$ are positive integers such that $displaystyle sqrt8+sqrt32+sqrt768=acosbigg(fracpibbigg)$



      what i try: i am trying to convert it into $displaystyle sqrt2+2cos 8x=sqrt2cos 4x$



      How do i solve it Help me please










      share|cite|improve this question









      $endgroup$




      If $a,b$ are positive integers such that $displaystyle sqrt8+sqrt32+sqrt768=acosbigg(fracpibbigg)$



      what i try: i am trying to convert it into $displaystyle sqrt2+2cos 8x=sqrt2cos 4x$



      How do i solve it Help me please







      trigonometry






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 12 at 10:09









      jackyjacky

      1,186715




      1,186715




















          2 Answers
          2






          active

          oldest

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          4












          $begingroup$

          You're on the right track. The surd is $$2sqrt2(1+sqrt2+sqrt3)=2sqrt2(1+sqrt2(1+costfracpi6))=2sqrt2(1+2costfracpi12)=4costfracpi24.$$So take $a=4,,b=24$.






          share|cite|improve this answer











          $endgroup$




















            3












            $begingroup$

            Hint: Your term is equal to $$2sqrt2+2sqrt2+sqrt3$$






            share|cite|improve this answer











            $endgroup$












              Your Answer





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              2 Answers
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              4












              $begingroup$

              You're on the right track. The surd is $$2sqrt2(1+sqrt2+sqrt3)=2sqrt2(1+sqrt2(1+costfracpi6))=2sqrt2(1+2costfracpi12)=4costfracpi24.$$So take $a=4,,b=24$.






              share|cite|improve this answer











              $endgroup$

















                4












                $begingroup$

                You're on the right track. The surd is $$2sqrt2(1+sqrt2+sqrt3)=2sqrt2(1+sqrt2(1+costfracpi6))=2sqrt2(1+2costfracpi12)=4costfracpi24.$$So take $a=4,,b=24$.






                share|cite|improve this answer











                $endgroup$















                  4












                  4








                  4





                  $begingroup$

                  You're on the right track. The surd is $$2sqrt2(1+sqrt2+sqrt3)=2sqrt2(1+sqrt2(1+costfracpi6))=2sqrt2(1+2costfracpi12)=4costfracpi24.$$So take $a=4,,b=24$.






                  share|cite|improve this answer











                  $endgroup$



                  You're on the right track. The surd is $$2sqrt2(1+sqrt2+sqrt3)=2sqrt2(1+sqrt2(1+costfracpi6))=2sqrt2(1+2costfracpi12)=4costfracpi24.$$So take $a=4,,b=24$.







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited Mar 12 at 11:30

























                  answered Mar 12 at 10:21









                  J.G.J.G.

                  30.3k23148




                  30.3k23148





















                      3












                      $begingroup$

                      Hint: Your term is equal to $$2sqrt2+2sqrt2+sqrt3$$






                      share|cite|improve this answer











                      $endgroup$

















                        3












                        $begingroup$

                        Hint: Your term is equal to $$2sqrt2+2sqrt2+sqrt3$$






                        share|cite|improve this answer











                        $endgroup$















                          3












                          3








                          3





                          $begingroup$

                          Hint: Your term is equal to $$2sqrt2+2sqrt2+sqrt3$$






                          share|cite|improve this answer











                          $endgroup$



                          Hint: Your term is equal to $$2sqrt2+2sqrt2+sqrt3$$







                          share|cite|improve this answer














                          share|cite|improve this answer



                          share|cite|improve this answer








                          edited Mar 12 at 10:23









                          J.G.

                          30.3k23148




                          30.3k23148










                          answered Mar 12 at 10:21









                          Dr. Sonnhard GraubnerDr. Sonnhard Graubner

                          77.8k42866




                          77.8k42866



























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