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mean and variance in backlog process


Birth and Death Process Question (Queuing)Comparing two Markov chainsM/G/1/K - evalutate birth and death ratesM/M/1 Queuing Theory QuestionPoisson process different type of eventsMulticlass Markov processIndependent Poisson processQueue serving packets in chunks: waiting time and output process?Question about Poisson ProcessProbability mass and mean of active users in a memoryless case system













0












$begingroup$


We have a discrete process $(N_k)_kinmathbbN$ defined as follows. At each time $k$ an amount of Poisson$(nu)$ packets come in, but there is also a probability $1/e$ that exactly $1$ packet leaves.



Example:
$N_1=3$



At $k=2$ exactly one of these three leaves. It could also have happened that nothing was left, with probability $1-1/e$, but let it do happen this time.



We run Poisson$(nu)$ and the outcome is $4$.



So $N_2= $3-1+4=6$.



My question is: how to calculate the mean and variance of this process? We assume $nu<1/e$, so the process is stable.



I know it is doable if we know the probability distribution $p=(p_1,p_2,...)$, but calculating $p$ is a lot of work, so maybe there is an easier way?



We can also see this as an $M/G/1$ queue with $Gsim$ geometric$(1/e)$, but then we will just get an approximation, because the Poisson-process here is continuous, not discrete.



Is there anyone with a nice idea?










share|cite|improve this question









$endgroup$
















    0












    $begingroup$


    We have a discrete process $(N_k)_kinmathbbN$ defined as follows. At each time $k$ an amount of Poisson$(nu)$ packets come in, but there is also a probability $1/e$ that exactly $1$ packet leaves.



    Example:
    $N_1=3$



    At $k=2$ exactly one of these three leaves. It could also have happened that nothing was left, with probability $1-1/e$, but let it do happen this time.



    We run Poisson$(nu)$ and the outcome is $4$.



    So $N_2= $3-1+4=6$.



    My question is: how to calculate the mean and variance of this process? We assume $nu<1/e$, so the process is stable.



    I know it is doable if we know the probability distribution $p=(p_1,p_2,...)$, but calculating $p$ is a lot of work, so maybe there is an easier way?



    We can also see this as an $M/G/1$ queue with $Gsim$ geometric$(1/e)$, but then we will just get an approximation, because the Poisson-process here is continuous, not discrete.



    Is there anyone with a nice idea?










    share|cite|improve this question









    $endgroup$














      0












      0








      0





      $begingroup$


      We have a discrete process $(N_k)_kinmathbbN$ defined as follows. At each time $k$ an amount of Poisson$(nu)$ packets come in, but there is also a probability $1/e$ that exactly $1$ packet leaves.



      Example:
      $N_1=3$



      At $k=2$ exactly one of these three leaves. It could also have happened that nothing was left, with probability $1-1/e$, but let it do happen this time.



      We run Poisson$(nu)$ and the outcome is $4$.



      So $N_2= $3-1+4=6$.



      My question is: how to calculate the mean and variance of this process? We assume $nu<1/e$, so the process is stable.



      I know it is doable if we know the probability distribution $p=(p_1,p_2,...)$, but calculating $p$ is a lot of work, so maybe there is an easier way?



      We can also see this as an $M/G/1$ queue with $Gsim$ geometric$(1/e)$, but then we will just get an approximation, because the Poisson-process here is continuous, not discrete.



      Is there anyone with a nice idea?










      share|cite|improve this question









      $endgroup$




      We have a discrete process $(N_k)_kinmathbbN$ defined as follows. At each time $k$ an amount of Poisson$(nu)$ packets come in, but there is also a probability $1/e$ that exactly $1$ packet leaves.



      Example:
      $N_1=3$



      At $k=2$ exactly one of these three leaves. It could also have happened that nothing was left, with probability $1-1/e$, but let it do happen this time.



      We run Poisson$(nu)$ and the outcome is $4$.



      So $N_2= $3-1+4=6$.



      My question is: how to calculate the mean and variance of this process? We assume $nu<1/e$, so the process is stable.



      I know it is doable if we know the probability distribution $p=(p_1,p_2,...)$, but calculating $p$ is a lot of work, so maybe there is an easier way?



      We can also see this as an $M/G/1$ queue with $Gsim$ geometric$(1/e)$, but then we will just get an approximation, because the Poisson-process here is continuous, not discrete.



      Is there anyone with a nice idea?







      stochastic-processes markov-chains markov-process queueing-theory






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 12 at 11:39









      Rocco van VreumingenRocco van Vreumingen

      928




      928




















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