Fdtxjr

Multi tool use

Is it a good idea to use CNN to classify 1D signal?

What would you call this weird metallic apparatus that allows you to lift people?

Can the Great Weapon Master feat's damage bonus and accuracy penalty apply to attacks from the Spiritual Weapon spell?

How fail-safe is nr as stop bytes?

What is the appropriate index architecture when forced to implement IsDeleted (soft deletes)?

Disembodied hand growing fangs

What do you call the main part of a joke?

Why does the remaining Rebel fleet at the end of Rogue One seem dramatically larger than the one in A New Hope?

What is this clumpy 20-30cm high yellow-flowered plant?

Morning, Afternoon, Night Kanji

How to tell that you are a giant?

How much damage would a cupful of neutron star matter do to the Earth?

What is the meaning of 'breadth' in breadth first search?

Take 2! Is this homebrew Lady of Pain warlock patron balanced?

What initially awakened the Balrog?

Most bit efficient text communication method?

SF book about people trapped in a series of worlds they imagine

Drawing without replacement: why is the order of draw irrelevant?

Illegal assignment from sObject to Id

Selecting user stories during sprint planning

Is grep documentation about ignoring case wrong, since it doesn't ignore case in filenames?

Project Euler #1 in C++

Is there hard evidence that the grant peer review system performs significantly better than random?

What is the difference between globalisation and imperialism?

Suppose $g$ is a symmetric bilinear form, is $operatornamerad g = operatornamerad(g+g^T)$?

0

$begingroup$

Is it true that, when we have a field $K$ with $operatornamechar(K) ne 2$, that $operatornamerad g = operatornamerad(g+g^T)$?

I know that in such a field, a bilinear form can be written as the sum of a symmetric and an alternating bilinear form.

How do I use this fact to prove the given statement?

Thanks.

linear-algebra

share|cite|improve this question

asked Mar 27 at 17:37

ZacharyZachary

3419

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  what is rad?...
  $endgroup$
  – daw
  Mar 27 at 20:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @daw the radical
  $endgroup$
  – Zachary
  Mar 28 at 15:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  If $g$ is symmetric this is trivial since $g=g^T$, isn't it?
  $endgroup$
  – daw
  Mar 28 at 15:16
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  So rad$g$=rad$(2g$)?
  $endgroup$
  – Zachary
  Mar 28 at 15:22
  

  
  
  
  

add a comment | 

0

$begingroup$

Is it true that, when we have a field $K$ with $operatornamechar(K) ne 2$, that $operatornamerad g = operatornamerad(g+g^T)$?

I know that in such a field, a bilinear form can be written as the sum of a symmetric and an alternating bilinear form.

How do I use this fact to prove the given statement?

Thanks.

linear-algebra

share|cite|improve this question

asked Mar 27 at 17:37

ZacharyZachary

3419

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  what is rad?...
  $endgroup$
  – daw
  Mar 27 at 20:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @daw the radical
  $endgroup$
  – Zachary
  Mar 28 at 15:11
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  If $g$ is symmetric this is trivial since $g=g^T$, isn't it?
  $endgroup$
  – daw
  Mar 28 at 15:16
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  So rad$g$=rad$(2g$)?
  $endgroup$
  – Zachary
  Mar 28 at 15:22
  

  
  
  
  

add a comment | 

$begingroup$

Is it true that, when we have a field $K$ with $operatornamechar(K) ne 2$, that $operatornamerad g = operatornamerad(g+g^T)$?

I know that in such a field, a bilinear form can be written as the sum of a symmetric and an alternating bilinear form.

How do I use this fact to prove the given statement?

Thanks.

linear-algebra

share|cite|improve this question

asked Mar 27 at 17:37

ZacharyZachary

3419

$endgroup$

share|cite|improve this question

asked Mar 27 at 17:37

ZacharyZachary

3419

share|cite|improve this question

asked Mar 27 at 17:37

ZacharyZachary

3419

asked Mar 27 at 17:37

ZacharyZachary

3419

asked Mar 27 at 17:37

ZacharyZachary

3419